Mapping sqrt() to √ symbol

[Bert Mariani]

Hello Mahmoud et ALL

I am trying to use the symbol  √  for  sqrt  for easier reading 

 √ = 0x221A

Is it possible ?

Sect 35.4

ChangeRingOperator <oldoperator> <newoperator>

example:   ChangeRingOperator  =  is

Code:

See "Sqrt: "+ sqrt(9) +nl

ChangeRingOperator  sqrt   √

 See " √  : "+ √(9)    +nl

Warning (W6) : Compiler command ChangeRingOperator - Operator not found!
Operator :  sqrt
Sqrt: 3

Line 60 Error (R3) : Calling Function without definition: √
in file 3D-Polar-Cartesian-1.ring

[Ilir Liburn]

Hello Bert,

sqrt is not an operator, it is a function. Command changeringoperator only works with single characters, for example ** or ^^ are not supported.

Instead, you should use function which wraps sqrt

? √(10)

func √ val

return sqrt(val)

Greetings,

Ilir

[Bert Mariani]

Thanks Illir !!

It work just fine.

[Ilir Liburn]

Hello Bert,

You're Welcome.

Greetings,

Ilir