Q: Python cannot find my file when executing, calling, etc.

[John Sintal]

Hi,

I hope it is okay for me to post a programming related question here. I hope it doesn't spam the entire group w/ this question. Let me know! I tried IRC, been it seems ppl are away from keyboard (AFK).

I am trying to run patch and/or git apply for my rb patch command (WIP here http://reviews.reviewboard.org/r/3440/). I think I get the string command correct. For example, my rb patch would generate a string like "git apply /tmp/tmpX/' or 'patch -pX < /tmp/tmpx'.

If I run that string in my terminal, the patch would work fine. However, every time I run it through execute(), call(), I get OSError: [Errno 2] No such file or directory.  I've also tried this on trivial files, such as the ones in the current directory, and I still get the same error. Clearly, python is not happy when it tries to find a file listed as an argument to a command. I've also tried \\ (double backslashes) and still no luck.

Any one got any hints to solve this issue? I've been stuck on this for quite some time.

[David Trowbridge]

John,

My guess is that you're passing in one big string where what is really expected is a list of arguments.

When you execute something from the shell, such as "git apply file.patch", your shell parses that up into three things: "git", "apply", "file.patch" and constructs an argv vector to invoke the process with. From your patch, I see you creating strings with the command as you might type it into your terminal, which you then (supposedly) pass into execute(...). I think it'll work better if you create a list of arguments like ['git', 'apply', '-p', p_num, patch_file] and then give that to execute().

-David

-David