Can't deserialize xml into subclasses

[Zac Smith]

I am trying to deserialize the following xml (abridged):

<?xml version="1.0" encoding="UTF-8"?>
<response>

  <result page="1" perPage="10" count="1">
    <document>
      <track>
        <genre id="37">
          <name>Rock</name>

        </genre>
      </track>
    </document>
  </result>
</response>


My DTO classes look like this:
        public class Track
        {
            public string Name { get; set; }
            public Genre Genre { get; set; }
        }

        public class Genre
        {
            public string Name { get; set; }
        }

The track Name property gets set, but the genre Name property does not.

Can anyone tell me why this is?

[Cristovão Morgado]

Try to put the id as an element <id>55</id>

Sent from my Lumia 800

---

From: Zac Smith
Sent: 06/03/2012 08:35
To: rest...@googlegroups.com
Subject: Can't deserialize xml into subclasses

[Zac Smith]

I don't have control of the xml format so I can't do that.

[John Sheehan]

are you using RootElement? also i don't see a track name anywhere in the sample data. am i missing something?

I don't know why Track.Name is being populated, only Genre.Name should be with the class defs you have. It might work with this (assuming root element is set to Track):

        public class Track
        {

            public Genre Genre { get; set; }
        }

        public class Genre
        {
            public string Name { get; set; }

            public int Id { get; set; }
        }

[Zac Smith]

Yeah sorry the xml should have been:

<?xml version="1.0" encoding="UTF-8"?>
<response>

  <result page="1" perPage="10" count="1">
    <document>
      <track>

        <name>Someone New</name>

        <genre id="37">
          <name>Rock</name>

        </genre>
      </track>
    </document>
  </result>
</response>

I tried setting the RootElement to 'track', but when I did that I didn't even get the Track.Name property set.

[Zac Smith]

My issue was that I had declared the DTO classes inside of another class. In my application I already have a Track class so I didn't want the DTO track class to interfere.

Is there anyway I can rename the DTO class to something other than Track?