Help with replacing functions myfunc(param1,0,param3) ----> myfunc(param1,param3,0,param3)

[Explorer]

Hi All,

Was looking fr a way to do the following replacement using regex

myfunc(param1,0,param3) ----> myfunc(param1,param3,0,param3)

([^,_]+),_([^,_]+),_([^,_]+),_([^,_]+) 

The above should help me get the param 3, however not sure how to replace using grouping constructs (\1,\2) etc

[iiz]

Search for

(?=\()([^)]*),([^)]*),([^)]*)(?=\))

replace with

\1,\3,\2,\3

basically you are looking for a string between brackets, not counting the brackets. Then creating numbered groups for backreferencing. Then you reference them in the replace query.

Op dinsdag 27 mei 2014 23:10:30 UTC+2 schreef Explorer: