Re: Redis Lua Problem?

[霍其坤]

try this

local t = {}

t[#t+1]=1

t[#t+1]=2

return redis.call('sadd','test',unpack(t))

发自我的 iPad

在 2012-12-17，2:13，Harachie <hara...@gmail.com> 写道：

Hi all,

I am working with the cool LUA feature.

To add multiple items to a set I want to simply add a LUA table via SADD.

Here is my test script:

local t = {}

table.insert(t, 1)

table.insert(t, 2)

redis.call('sadd', 'teststst', t)

return 0

The thing that makes me wonder is this line 'redis.call('sadd', 'teststst', t)'

It does simply nothing,

but I would expect to have added every entry from the table to the set.

My current workaround it to do this in a simple for loop.

Is this supposed to work, or am I missing something?

It does not throw any error, so I have no idea if this is the expected behaviour ;-).

Hope any one can shed some light onto this.

Kind regards,

Bastian Kröger

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[Bastian Kröger]

Hi,

it works as expected,

thanks for the help :-)

Kind regards,

Bastian Kröger