I would try:
[#........#].replace(.,)
the first parameter is a . and the second parameter is completely
empty and they are separated by a comma.
Quote marks seem to be unnecessary so that's the way I regularly use
it. It may also work with single or double quotes if you prefer it,
but I've never used them:
[#........#].replace('.','')
[#........#].replace(".","")
The java.lang.String prefix is just a Java convention for showing the
type of parameter expected and should not be reproduced when you
invoke the function.
Jonathan