Eugene,
Transistors love voltage, just don't over do it !!!
A lot of folks run their rigs at 16 volts,, Not only will you see a
slight increase in transmit performance but you will without doubt see
a hotter receiver as well, especially on SSB..
Understand however that the components inside your rig have voltage
ratings, particularly the caps, and by exceeding the working voltage
you will destruct them.. There are also resistor biasing networks that
set up the correct operating points for the transistors and if you
increase the voltage to them you will also increase the heat or
operating wattage that they are rated for; the I.C.'s fall under this
same catagory since it is the heat that they cannot dissipate due to
the increased voltage...
Keep in mind that while you will reap some benefits, the hotter
receiver in particular, you will also be shortening your rigs overall
life expectancy and if there was something on the way out,
the 16 volts will surely help you find out what it was..
In other words run the 16, do it conciously, and if there comes the
moment when something goes, don't take it as a surprise..
Just enjoy it till it does or till it never does... !!!!
P.S. I run all my radios at 15.0 volts.....
(your 16 is 1 volt too high for my sanity)
Eugene,
A simple application of Ohm's law applied to your question will validate your
theory... (hint - what is the result of voltage multiplied by current, and what
is it's unit of measure?)
73's,
<<< DAN >>>
--
+-------------------------------------------------------+
|An Armed Man is a Citizen, an Unarmed Man is a Subject.|
+-------------------------------------------------------+
In article <19970329031...@ladder01.news.aol.com>, t6...@aol.com (T6766) writes:
>So I now run it on about 16 Volts,
>but the radio needs only 13.8 Volts, and it seems to work best with about
>16 volts. If anyone can confirm or deny this theary, please post it here.
Nor can we deny...
You're taking chances running the radio with that high of a voltage constantly.
As said in an earlier post - there are voltage sensitive components that are
put there in an effort to reduce manufacturing costs and yet be still well within
limits of a typical automotive electrical system - and not cause a fire or
a blown radio.
The radio you're using needs good regulation - but can operate at a slightly
higher voltage. There are other voltage sensitive areas that can tolerate
higher power supply voltages - but if their maximum level is exceeded -
you'll find your room filled with "Magic Smoke", a burned out radio, and
it's power supply too - along with a startled, then pissed - operator.
"Slightly" is left open for interpetation here...;-)
"pissed" too... ;-?
Yes, you will produce more wattage, and more heat - you can't have one
without the other in this type of situation - operating your radio like that.
There are other things that you'll also find out - not only with the aforementioned
postings, but other less noticable things that experience will teach you.
I'll also admit I've had my share of fun/sad/experiences like this too -
Just look at the Carbonized, Charred-Chassis, carcasses laying around
my shack performing assorted duty offices like paperweights and mementos.
Someday, you'll collect enough debri to understand...
Once you've started smoking...it's hard to quit - OH! The Smell! ;-)
ROTFL!!!
Yes, it is a slow news day...Happy Easter!
~~~One final note from the Litter Box:~~~
ATTENTION COMMERCIAL E-MAILERS!:
Please REMOVE this address from your
list - you're wasting your time!
- Thank You.
Eugene,
Even though you feed the radio with 16 volts that does not mean your
getting more power out..The internal regulators are just being taxed to
there max..They are desinged to bring 13.8 volts down to 12 & 5 volts
which is what most of the circuts use..In a nut shell your heading
toward premature failure of the radio..Go to Radio Shack and buy a 12
volt power supply,make sure its the regulated one..Match the antenna to
the radio and you will get all the radio has to offer..
Best of Luck
The Wizard (Rick)
Here's the deal, Bucky. The engineers designed your radio (and all
other CB's too) to operate at a DC input voltage of 13.8. There is a
small amount of variation acceptable either higher or lower. You will
get more power out of the radio with a higher voltage applied, but it
will result in a fried radio in a short time. You make the call.
Nobody will ever notice the difference in your signal, is it worth it?
Boy, real constructive. What if he did hook into 220? Post mortem
regrets.
The radio will, to a point perform better with more voltage. How long
it will keep working is another thing (until it breaks from too much
voltage) :-). It will put out more at more than 13.8; but you don't
really want to run it there as it will shorten the life of the radio,
possibly considerably shorten. Run it at 12-14, 15 if you absolutely
have to.
Yes, in a car, the voltage can be 14.8-15 or a little more, but why
operate the radio out of design parameters when you don't have to?
In conclusion, just keep it as close to 13.8 as is reasonably possible.
But you may get some hum with your transmitted signal since that power
adapter may not be able to give enough current. :)
73,
Mike
I've never seen a CB radio that regulated the voltage supply to the
final transistor!
Wait, I vaguely recall that the old Radio Shack TRC448 had a
configuration like that. However, it had trouble putting out 12Watt PEP
on SSB.
More input voltage will invariably give you more power. It will also
incur other problems too, though. Expensive problems! !
Cheers!
--
Andy Moss
"In God we trust - the rest can pay cash......."
Be careful when using voltage over about 15 volts. Many products are
protected from over volatge by using a 16 volt zener diode across the
incoming power line. When voltage exceeds 16 volts, the zener diode will
begin to clamp down and draw excessive current through the fuse.
Hopefully the fuse will blow at this point and everything will be OK,
but I have seen cases where the zener diode pops too. Not a big deal
because you can simply remove it and defeat the protection that it
offers, but you are better off keeping your power supply no higher than
16 volts to avoid such problems to begin with.
73 from Steve
I tested many of my radios in an attempt to find the optimum voltage
to power ratio. The units failed most often when above 16 volts. I would
recommend you maintain the standard 13.8 - 14 volts on base units. Mobile
operation at 16 volts, two 8 volt lead-acid batteries in series, are often used
by the so-called high powered operators with good luck.
I believe the voltage drop in the power cables used keeps the voltage
levels lower at perhaps 14 volts. Really those units are safe 'cause the voltage
keeps droppin' as they keep talkin'.
Carl
The2x4
> T6766 wrote:
> >
> > Hi,
> >
> > I have a Cobra 18RV Mobile CB radio. I have tried several DC power
> > supplies
> > (including Radio Shack and Uniden types) and I think I have come to a good
> > conclusion. When I use a 9 Volt power adopter, the S/TX meter only goes
> > up to about three (3) LEDs. When I use a 12 Volt adopter, it goes to four
> > (4) LEDS. And finally when I use a tunable power supply that goes from
> > 3-17 Volts, I find that the more Volts input I give, the more LEDs light
> > up, which seems to mean that more RF power is being radiated from the
> > unit. So I now run it on about 16 Volts,
> > but the radio needs only 13.8 Volts, and it seems to work best with about
> > 16 volts. If anyone can confirm or deny this theary, please post it here.
> >
> > Thanks,
>
>
I've tried cranking up the DC power on my radio too, it does work
a little with radios that have no power (or poor ) regulation in them. I
know that for sure because I checked my radiated power with a field
strenght meter. At about 16 volts the radio worked well, even seemed to
give better audio quality as well as more RF output.
CHRASH
hello-
Can I use the cord of a old heater. Does it make any diferance what
wire goes to the hot side. thanks Mike
You DO NOT EVER want to plug in a 12 Volt radio into the wall with a
cord. Meaning putting 120 Volts into a radio designed for 12 volt input
unless you want:
1. Your radio to be immedieately fried.
2. Yourself possibly killed or injured.
Thanks Joel for the initial idea of directly plugging it in in the first
place :(.
You will need a 12-13.8 Volt power supply like the ones they sell at
Radio Shack. Just tell them you have a CB and want a power supply for
it and they should know what to get for you. Radio Shack is probably
not the cheapest place but the best for a beginner :-).
73,
Mike
--
Now your kidding i know. Im not stuped. ok. Mike
T6766 <t6...@aol.com> wrote in article
<19970329031...@ladder01.news.aol.com>...
The reason why this works is that most CB radios are designed to work
within the automotive environment. Most auto electrical systems vary in
their voltage output from 12 volts up to about 16-17 volts. The CB will
operate on anything from 10 volts or so up to around 15-16 just fine and
you will get more output power simply due to the fact that the output
transistors have more to work with. However it is still illegal to operate
with more than 4 watts output.
Eugene it is simple P=IE which is Power equals volts times current.
All though I (current) is more important. A CB radio is AM which using
CB slang "Swing" is more important. On 9 volts the radio is not
getting enough volts (no matter how much current is available) to
drive the radio to full legal output power. At 16 you all it can
handle which is actually to much and is bad for the radio in the long
run. Also if you use the variable power supply, when it is on 16 volts
you have less current available to the radio, so you loose "swing". It
would be best to use a battery because you have constant voltage with
needed current on demand. Also with a battery you have no power supply
AC ripple on the DC sorce. Warning: Remember never ever run the radio
with a charger hooked to the battery. But if you run it off the PS set
it for about 14.5 to 15.0 VDC. This is safe and most good fixed high
current PS for 13.8 VDC car equipment put out about 15 VDC at 7 to 10
amps. Also if you are carefull with your wiring and know that
everything is hooked correctly, you may want to check the fuse value.
A low number means faster, better protection, but also means that it
will limit current flow during the "swing" of the AM RF signal. I have
put 5 amp fuses in my power cord when it came with a 2 amp from the
factory. The only real draw back to this is if the radio shorts, it
gets more current before the fuse blows, meaning more damage can
happen inside the radio before power is removed. Do not go to big on a
fuse size increase. The radio can only use so much current and if it
does short you do not want to burn down the place. The best clue that
the radio needs to go up one size is clipping due to lack of current
or a bent or glowing fuse during heavy use (assuming the radio has no
defects or shorts of course).
Remember to be carefull and the higher voltages only shorten the life
of your radio. Current is more important. And if you radio puts out 7
watts at 14.5 volts and 9 watts at 16.5 volts, nobody can hear the
difference and you are not talking any farther. The difference of 2
watts is unhearable and is not even 1/100 of an S unit. In other words
it is not worth the trouble or the reduced life span of the radio.
>A CB radio is AM which using
>CB slang "Swing" is more important.
Swing this. The amount of energy in the sideband is what is important.
That is, the energy in the sideband AND within the receivers bandpass
limits. If you want more swing don't hold a golf ball between your
cheeks when you walk.
>On 9 volts the radio is not
>getting enough volts (no matter how much current is available) to
>drive the radio to full legal output power.
i thought you said 'current was more important'....
>At 16 you all it can
>handle which is actually to much and is bad for the radio in the long
>run. Also if you use the variable power supply, when it is on 16 volts
>you have less current available to the radio, so you loose "swing".
>
Are you making this up? You do not 'loose swing' because there is
'less current available'... There may be a number of factors which
would cause the radio to reduce it's output when modulated. Current
limiting is indeed one of them but to authoritatively state that is
the case here is bull crap. In fact in this case it is probably NOT
the relevant factor. More likely, a regulator in the radio or a
specific component's gain is limiting the maximum peak output.
16 volts may be slightly stressing the components in the radio, but it
is primarily a thermal issue at this voltage. If you tend to 'key-up'
for long intervals you'd better watch the temperature of that final!
> It
>would be best to use a battery..... <EDIT CLIP>
>
Ah, don't do this. It's a dumb idea. To get a large enough battery to
last for more than a few minutes you'll have to get a lead-acid type
like a car or marine battery. Charging that thing in the house is
absolutely crazy. Even so called 'sealed' gelcel types can out-gas
combustibles (hydrogen) when charged. If you can keep the charge rate
low enough you might get away with it, but is not really a safe
practice...
>Remember to be carefull and the higher voltages only shorten the life
>of your radio.
>
Ok. So what. The question is: How much will it shorten it?
>Current is more important.
Nope.
>And if you radio puts out 7
>watts at 14.5 volts and 9 watts at 16.5 volts, nobody can hear the
>difference and you are not talking any farther.
Yep. Going from 7 to 9 watts isn't going to make a noticeable
difference.
-=>
-=>
-=> When does the P in p=i*e =rf power output??
-=>
-=> I have not seen this equation work out yet say 14 volts * 100 amps
-=>doesn't =1400 watts rf output.
-=>
-=>
-=>
it does not equal power output.
Its Ohm's law - but the correct way to use in this application would be
For 1400 Watts at 14 volts, you need to supply 100 amps. But that is only
in theory, you would need more current because of loss.
HYPE <cus...@clinton.net> wrote in article <336A16...@clinton.net>...
> Brian Ellsworth wrote:
> -
> - On Thu, 01 May 1997 06:07:34 GMT, ke4...@radia1.com wrote:
> - -Eugene it is simple P=IE which is Power equals volts times current.
> - -All though I (current) is more important.
> - -
> - My fifth grader read this, saw the obvious contradiction and asked me
> - which (if either) of these statements is true... First year electronic
> - students will assure us the equation is true. (although i doubt it is
> - very relevant to answering the original question.) The statement about
> - current being 'more important' is a joke. Any fifth grade math student
> - will back me up on this one.
> -
When does the P in p=i*e =rf power output??
I have not seen this equation work out yet say 14 volts * 100 amps
> When does the P in p=i*e =rf power output??
After you factor in efficiency.
>
> I have not seen this equation work out yet say 14 volts * 100 amps
> doesn't =1400 watts rf output.
Using your example: 14 volts times 100 amps equals 1400 DC watts
INPUT. No amp is 100% efficient. You have to consider the
efficiency of the amp. Most of the CB-grade RF amps out there
are between 55 and 65 percent efficient. That means the amp
in your example would put out between 770 and 910 watts of
RF power.
So, if you want to figure output power from input power,
the equation would look something like this:
DC Voltage X DC Current = Input Power X Efficiency = Output Power
You should remember that. It's the cheapest way I know of to
realistically judge an amplifier's output power. It's alot
easier come up with an accurate volt meter and DC ammeter than
it is to come up with an accurate wattmeter and high-power
dummy load combo.
--
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You must figure in the power drawn by all the radios circuitry and then
the efficency of the equipment.
that would only be correct if the current and the voltage were in phase.
We're talking AC here not DC - 50 ohms is the 'impediance' not the
resistance. It is a load for the output
Huh? This is not correct in any way.
Nobody said voltage times current was power output! 50 ohms and 14
volts has nothing at all to do with it. Go read a book about this stuff
if you want to know.
Marty Kirkland <mkir...@electrotex.com> wrote in article
<337127...@electrotex.com>...
Got some of you thinking I have seen a numerous of times on this news
group that people use the equation p=i*e in reference to power output as
in rf power = current times volts. when the p is total power displaced by a
transmitter or amp .
and no 2 amp are of the same efficiency. why do we put heatsink on amps? To
displace the heat from the transistors this is also power output so how do
you figure this in? This equation does not work in rf applications.