Am I looking at this wrong? Can someone explain an example where this isn't
the case?
Thanks,
Lou
The real question is why you would want to - apart from curiosity?
-Bill
I was always confused by the shorter antennas having a lower input Z. If
the trend continues all the way down to an infinitely small antenna, then an
empty connector (open circuit) is a dead short...
:-)
What if the transistor was trying to feed a current into an open circuit ?
Then the voltage would reach infinity and damage the transistor.
J. Harvey
Ottawa
de VE1...@rac.ca /VE3
Hi Bill,
Not a fair response because we've all done it without the benefit of
curiosity (and for no good reason why to boot).
73's
Richard Clark, KB7Q
"Lou" <lo...@nospam.com> wrote in message
news:uxyO7.73628$Ze5.41...@news1.rdc1.md.home.com...
I guess that I wouldn't per se want to. But if someone tells you not to do
something it certainly makes you wonder. I guess you could say, it makes me
question how well I understand amplifier design.
Shorter antennas have a lower input R but a higher input X which
equates out to a *higher* input Z. Z^2 = R^2 + X^2 where X^2
goes up faster than R^2 goes down.
--
cheers, CAM http://www.qsl.net/w5dxp
Example 1, if there's a Pi output network and the external load is
disconnected then the output transistor sees a zero-resistance load
at full current and blows up.
Example 2, if the external load is short-circuited, in order to
keep full current flowing into the very high inductive network
reactance an excessive voltage is developed across the output
collector which then breaks down.
" Troll's " are mischievous little dwarfs who live in deep dark
caves under Scandinavian mountains.
Pete
"Lou" <lo...@nospam.com> wrote in message
news:uxyO7.73628$Ze5.41...@news1.rdc1.md.home.com...
Dave WD9BDZ
There is a 50-ohm coax r-f output in most cases. A wave has been
generated and is traveling to the coax connector. Where it encounters an
open-circuit, current is interrupted. Energy in the H-field has no place
to go other than to the E-field, causing a voltage double. This is
called the Ferranti Effect. Some transistors can`t take it.
Best regards, Richard Harrison, KB5WZI
I was just kidding. Unfortunately I can't answer the question either.
Just a SWAG, I suspect if the transistor had zero components following
it, then theoretically your guess would be correct. But in practice you
have harmonic filters, metering and even the choked and bypassed Vcc
line and I suspect THEY would become the load in the absence of an
antenna.
-Curious Bill
-Bill