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Re: More on R + jX vs. SWR

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Nordic Breeds WA4VZQ

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Jan 24, 2011, 5:11:42 PM1/24/11
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"Edward Knobloch" <al...@nowhere.net> wrote in message
news:XtOdnfg4gP_SUqDQ...@giganews.com...
> Hi, Gang
>
> I recently posted about a DOS program by KQ6RH,
> to convert from RX noise bridge knob settings
> to impedance, in both polar and rectangular form:
> http://www.antenna-magic.com/Rx_brdg.htm
>
> My only "complaint" was that his program didn't also
> output the SWR for a 50 Ohm system.
>
> I realize that I can get the SWR info
> from a Smith chart, but the charts I have found
> for free download are centered on R=1,
> and require quite a bit of squinting to use.
>
> Anyway, I stumbled upon a very handy graph
> of SWR vs. R +jX (for SWR < 3.5:1 ),
> appearing in RCA Ham Tips for Dec 1956:
> http://bama.edebris.com/manuals/rcahamtips/rca1604/
>
> 73,
> Ed Knobloch


Ed,

The Smith Charts with R=1 in the center are normalized charts. If you
have 50 ohm coaxial cable, just multiply the numbers by 50. You may
occasionally use 75 ohm cable. While you can buy charts with R=75 in the
center, all you have to do with a normalized chart is to multiply the
values by 75. I doubt if you can even buy charts specifically for 93 ohm
(RG-62) cable, 300 ohm twinlead, or 450 and 440 ohm "window" line.

I always compute the reflection coefficient from a complex load before I
calculate the VSWR.

? (Greek capital letter Gamma) = (Zmeas - Zline)/(Zmeas + Zline)

We usually think that we can replace the line impedance with 50 + j0, but
as my friend Tom, K7ITM, often points out, so-called 50 ohm cable no
longer has a purely resistive characteristic impedance at low
frequencies. So we need to calculate the reflection coefficient as a
complex number. Once we have this, we need to determine the magnitude of
the reflection coefficient.

? (Greek lower case rho) = |?|

= sqrt(Real*Real + Imag*Imag)

Once we know the magnitude of the reflection coefficient, which is always
less than or equal to unity, the voltage standing wave ratio is simply

VSWR = (1 + ?)/(1 - ?)

If you have Windoze, all of these calculations are easily done in Excel.
You may have to install the Analysis Toolpack to get Excel to handle
complex numbers.

I strongly suggest that you continue to use Smith charts. The first
large program for my TI-59 calculator nearly forty years ago was an
electronic Smith chart. It was handy. but I continued to use Smith
charts because they offer graphically significant insight into what
happens along the length of a transmission line. Additionally, they help
you catch mistakes.

73, Barry WA4VZQ

Postscript: I used rich text format solely because I could use Greek
letters. Gamma and rho are almost universally used to represent the
complex reflection coefficient and its magnitude respectively in
engineering publications.

Cecil Moore

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Jan 25, 2011, 7:09:11 AM1/25/11
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On Jan 24, 4:11 pm, "Nordic Breeds WA4VZQ"

<ABSOLUTELYwa4vz...@SPAMlive.com> wrote:
> Postscript:  I used rich text format solely because I could use Greek
> letters.  Gamma and rho are almost universally used to represent the
> complex reflection coefficient and its magnitude respectively in
> engineering publications.

When I read the posting, both Gamma and rho are displayed as a '?'.
--
73, Cecil, w5dxp.com

J.B. Wood

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Jan 26, 2011, 6:58:09 AM1/26/11
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On 01/24/2011 05:11 PM, Nordic Breeds WA4VZQ wrote:

> We usually think that we can replace the line impedance with 50 + j0, but
> as my friend Tom, K7ITM, often points out, so-called 50 ohm cable no
> longer has a purely resistive characteristic impedance at low
> frequencies. So we need to calculate the reflection coefficient as a
> complex number. Once we have this, we need to determine the magnitude of
> the reflection coefficient.

Hello, and I believe some clarification is needed here. First, for most
ham radio applications we can assume a real characteristic impedance for
the transmission line (e.g. Zo = Ro = 50 ohms). The only time this
leads to large errors when calculating the line-transformed load
impedance (e.g. an antenna at a given frequency) occurs when the VSWR of
the load is greater than 10 or 20. (This was pointed out in a 1953 AIEE
paper by W. W. Macalpine.)

However, just because the reference impedance, Zo, is assumed to be real
doesn't mean that the reflection coefficient has to be real. Sincerely,
and 73s from N4GGO,

--
John Wood (Code 5520) e-mail: wo...@itd.nrl.navy.mil
Naval Research Laboratory
4555 Overlook Avenue, SW
Washington, DC 20375-5337

Nordic Breeds WA4VZQ

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Jan 27, 2011, 7:39:30 PM1/27/11
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Read this in a fixed-width font for the table to show properly.
 
"J.B. Wood" <john...@nrl.navy.mil> wrote in message news:ihp28k$gcg$1...@ra.nrl.navy.mil...
Thanks for commenting, James.

I decided to calculate the characteristic impedance of Times Microwave LMR-240 cable at several frequencies just to see.  This is basically a foamed dielectric version of RG-58 and I had the data handy.

The equation for characteristic impedance is:

    Zo = sqrt[ (R + j*w*L) / (G + j*w*C) ]

where: R = distributed series resistance, Ohms/meter
       L = distributed series inductance, Henries/meter
       G = distributed shunt conductance, Siemens/meter
       C = distributed shunt capacitance, Farads/meter
       w = radian frequency, 2*Pi*f, radians/second.
 
For LMR-240, Times gives:
 
Inner Conductor Solid BC 0.056 in (1.42 mm)
Dielectric Foam Polyethylene 0.150 in (3.81 mm)
Outer Conductor Aluminum Tape 0.155 in (3.94 mm)
Overall Braid Tinned Copper 0.178 in (4.52 mm)
 
Velocity of Propagation  84%
Dielectric Constant NA 1.42
Time Delay nS/ft (nS/m) 1.21 (3.97)
Impedance ohms 50
Capacitance pF/ft (pF/m) 24.2 (79.4)
Inductance uH/ft (uH/m) 0.060 (0.20)
Shielding Effectiveness dB >90
DC Resistance
Inner Conductor ohms/1000ft (/km) 3.2 (10.5)
Outer Conductor ohms/1000ft (/km) 3.89 (12.8)
Voltage Withstand Volts DC 1500
Jacket Spark Volts RMS 5000
Peak Power kW 5.6
So with this data, assuming the resistance is constant with frequency (reasonable considering the skin depth), we get:

    R = (10.5 + 12.8)ohms/1E3-meters = 0.0233 ohm/meter
    L = 0.20 uH/meter = 2E-7 Henry/meter
    C = 79.4 pF/meter = 7.94E=11 Farad/meter
 
To get G, we know that the dielectric is foamed polyethylene with a resistivity of 1E16 ohm-cm, or 1E14 Ohm-meter.  The equation for conductance in the concentric configuration of coaxial cable is:
 
    G = G = 2*Pi*Sigma/ln(B/A) = 6.283E-14/ln(3.81/1.42) = 6.366E-14 Siemans/meter
 
At this point, I used Excel 2003 with the Analysis Toolpack to do the caculations with complex numbers.  While Excel does the calculations without difficulty, Microsoft never thought about formatting complex numbers, so the following table is edited from Excel by hand. :-(  apologize for any transcription errors.
 
Frequency, Hz    Characteristic Impedance, Ohms        Magnitude        Phase, degrees
  1.000E00           4832.837 - j4831.960               6834.044         -44.4994
  1.000E01           1528.565 - j1527.717               2161.115         -44.9842
  1.000E02            484.545 - j481.932                 683.409         -44.8455
  1.000E03            156.989 - j148.750                 216.284         -43.4564
  1.000E04             62.551 -  j37.333                  72.845         -30.8304
  1.000E05             50.402 -   j4.633                  50.614         - 5.2521
  1.000E06             50.191 -   j0.465                  50.193         - 0.5311
  1.000E07             50.189 -   j0.001                  50.187         - 0.0531
 
So as we go increasingly below one MegaHertz, the characteristic impedance of the cable increases to above 50 ohms and it becomes increasingly capacitive.  If the FCC grants hams a band in the LF region, we might have to consider this.  But then, our cables will be very short in terms of wavelength.
 
        73, Dr. Barry L. Ornitz     WA4VZQ

K7ITM

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Jan 31, 2011, 2:32:10 AM1/31/11
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On Jan 27, 4:39 pm, "Nordic Breeds WA4VZQ"

<ABSOLUTELYwa4vz...@SPAMlive.com> wrote:
> Read this in a fixed-width font for the table to show properly.
>
>
>
> "J.B. Wood" <john.w...@nrl.navy.mil> wrote in messagenews:ihp28k$gcg$1...@ra.nrl.navy.mil...

> > On 01/24/2011 05:11 PM, Nordic Breeds WA4VZQ wrote:
>
> >> We usually think that we can replace the line impedance with 50 + j0, but
> >> as my friend Tom, K7ITM, often points out, so-called 50 ohm cable no
> >> longer has a purely resistive characteristic impedance at low
> >> frequencies.  So we need to calculate the reflection coefficient as a
> >> complex number.  Once we have this, we need to determine the magnitude of
> >> the reflection coefficient.
>
> > Hello, and I believe some clarification is needed here.  First, for most
> > ham radio applications we can assume a real characteristic impedance for
> > the transmission line (e.g. Zo = Ro = 50 ohms).  The only time this
> > leads to large errors when calculating the line-transformed load
> > impedance (e.g. an antenna at a given frequency) occurs when the VSWR of
> > the load is greater than 10 or 20.  (This was pointed out in a 1953 AIEE
> > paper by W. W. Macalpine.)
>
> > However, just because the reference impedance, Zo, is assumed to be real
> > doesn't mean that the reflection coefficient has to be real.  Sincerely,
> > and 73s from N4GGO,
>
> > --
> > John Wood (Code 5520)        e-mail: w...@itd.nrl.navy.mil

Barry's assumption of resistance being the same as the DC resistance
and independent of frequency will make the characteristic impedance
look closer to resistive than it actually is, at frequencies where
skin depth is small compared with conductor thickness. Since in
copper, skin depth at 1MHz is only about 2.6 mils (and is inversely
proportional to the square root of the frequency), the resistance of
that particular line's conductors at 1MHz will be considerably higher
than the DC resistance.

Dare I mention that when the line impedance is reactive, you can get
reflection coefficients with magnitude greater than unity? Seems like
every time that comes up here, someone gets their knickers in a knot
about it. Reflection coefficient = rho = (Z-Zo)/(Z+Zo), so if Z (the
load impedance) is a pure inductance, say +j50 ohms, and the line
impedance is (from Barry's chart) 50.4-j4.63 ohms, then rho =
-0.0134+j1.096, and |rho| = 1.096. But to calm your nerves, calculate
what the impedance is looking into any length of that line you wish,
terminated that way, and you'll see that the impedance never has a
negative real part.

Cheers,
Tom

John - KD5YI

unread,
Feb 7, 2011, 9:50:52 PM2/7/11
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For a Smith Chart which allows any Zo you wish, try:

http://www.fritz.dellsperger.net/PartInterests.htm

I love this chart. I used the free version for years.

Cheers,
John

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