Here's what I have after my initial attempt, about 45 minutes:
1. FALL : AUTUMNAL :: SPRING : Vernal
2. ONE : MONO- :: FEW : Oligo-
3. SMALL : LILLIPUTIAN :: LARGE : (?) (Blefuscudian was my initial
guess, but it's definitely wrong).
4. * : ASTERISK :: ə : Schwa
5. LETTER : POSTSCRIPT :: WILL : Cocidil
6. LIFE : VITAL :: BIRTH : Natal
7. 8 : OCTAVO :: 2 : Folio
8. FEAR OF STRANGERS : XENOPHOBE :: LOVE OF CATS : Ailurophile
9. NEAR THE SUN : PERIHELION :: FAR FROM EARTH : Apogee
10. ILLNESS : RELAPSE :: CRIME : Recidivism
11. TINTINNABULATION : ONOMATOPOEA :: BITTERSWEET : Oxymoron
12. TAUGHT BY ANOTHER : PUPIL :: TAUGHT BY ONESELF : Autodidact
13. SPRIGHTLY : MERCURIAL :: MOROSE : (?) (I can't think of the word
for this one)
14. DISEASE : PATHO- :: PHYSICIAN : Iatro-
15. 20 : 21 :: POUND : Guinea
16. SCRIPTURE : SUTRA :: INVOCATION : Mantra
17. GIFT : POISON :: LEER : Blank
18. BEND ONE'S KNEE TO : GENUFLECTION :: TURN ONE'S BACK ON : (?)
(Stuck again)
19. JAW : PROGNATHISM :: GLUTEAL FAT : Steatogypia
20. The answer is Apothem.
21. NOURISHMENT : ALIMENTARY :: GAMES OF CHANCE : Aleatory
22. ALPHABET : HIEROGLYPHICS :: ARCHIMEDES' SCREW : (?) (Does anyone
know about ancient machinery?)
23. GENERALIZED : LOCALIZED :: ANEMIA : (?) (No clue. What do you call
a localized loss of red blood cells?)
24. The answer is Schrodinger.
I haven't begun the non-verbal section yet. I'll regularly update this
post with more answers.
Brobdingnagian, I assume
>13. SPRIGHTLY : MERCURIAL :: MOROSE : (?) (I can't think of the word
>for this one)
Saturnine
Alan
--
Defendit numerus
Who uses te Mega Test? I though it was the Titan Test
that was popular with the crackpots.
> but I haven't seen the answers anywhere online.
Because everyone's busy compromising the Titan Test?
>If anyone wants to help me publish the
> answers. that'd be cool.
Cool? We need more idiots walking around thinking they're
special?
And what is it this measures?
>
> I haven't begun the non-verbal section yet. I'll regularly update this
> post with more answers.
Why don't you give it a miss?
Calm down mensanator. It's just the Brain Breaker, not the real deal.
=P
Then why are you going to the trouble of compromising the test?
> =P
It's a joke. That's what you don't understand. Take a deep breath.
First of all, the Brain Breaker was easy. No trouble at all.
Second, the answers were readily available after it was published, so
I couldn't do anyone any harm even if I wanted to with these answers.
It's so amusing the way people like you freak out when answers to a
little test get leaked to the internet.
Just to see Mensanator freak out, someone should post the real answers
to the Mega right here. That would be funny.
You need to learn how to relax. Seriously. It was a joke. And even if
it wasn't, what does it matter?
My guess is that mensanator's attitude to these tests is similar to
yours. And like me, he finds them sufficiently boring that he never
read enough of your posting to realise that it was a joke. And then,
you didn't read enough of his reply to realise that he despises these
tests as much as you do.
Nick
--
Nick Wedd ni...@maproom.co.uk
You're being quite presumptuous. You see, I know that it's not about
the test. It's about inflated egos, "moral integrity", and proving an
opposite viewpoint. Mensanator hates people who compromise tests
because it apparently somehow implies that the publisher of answers is
amazingly superior to the general population, and has a gigantic ego
simply because they have the power to "spoil the fun for others". Or
something to that effect. It's not the best way of describing the
situation. I think you both understand what I mean though.
I disagree that Mensanator hates the tests. He just hates people that
ruin it for others from what I can tell. To avoid erring on the
situation, I invite the esteemed Mensanator to comment on the
situation, so my presumptuous ideas can be checked by the actual facts.
Not quite.
> It's not the best way of describing the
> situation. I think you both understand what I mean though.
>
> I disagree that Mensanator hates the tests.
Yes, I do not hate the tests.
> He just hates people that
> ruin it for others from what I can tell.
Not quite true either.
> To avoid erring on the
> situation, I invite the esteemed Mensanator to comment on the
> situation, so my presumptuous ideas can be checked by the actual facts.
Ok, here's where I'm coming from:
Newsgroups: rec.puzzles
Subject: Answers to the Titan Test (a phoney IQ test)
Date: 1 Apr 2005 11:11:43 -0800
<quote>
Their main club is the "Mega Society" which
they say is reserved for those with
one-in-a-million IQ's, ie above 176. Of course
for good reason conventional IQ tests do not
have a scale that reaches such a
height, so they have created what they claim
is a test that can measure the intelligence of
those with very high IQ's.
When I first heard about this four years ago,
I decided to put a stop to this by publishing
the answers to their current test, the Titan Test
(notice again their extreme vanity in choosing
this name). This had been done before, to their
Mega Test, which they had to then abandon as
a criterion of membership.
</quote>
Note the very last sentence. This is a very long
thread on the validity of IQ tests measuring
intelligence vs IQ testing being crackpot science
used by quacks.
Now, if your intent was not similar to the above,
I hope you understand why I thought it was.
My very id (mensanator) is intended as a mockery
of High IQ societies:
It's not a name, it's a Title:
---------------------------------------------------
mensanator - n. Old Norse 1. slayer of the Mensa
In the autumn of 1996, the Mensa were holding their
annual All Hallows Eve Festival, when, unbeknownst
to them, a traitor in their midst raised the
portcullis of their fortress and allowed a Viking
raiding party to slip in, whereupon they slew the
entire host with the jawbone of an ass and carried
off the great prize.
Upon the great warrior chieftan, Paul the Berserk,
was bestowed the title "Mensantor" in honor of
that great victory.
---------------------------------------------------
But our interests are similar, interestingly enough. You and I could
get along very well =)
Where we differ is that while you question the validity of their
methods, I simply poke fun at it.
I guess you thought I was trying to prove something about myself to
other people, like how "intelligent" I am. My desires parallel no such
tangent.
That makes no sense. I would never consider passing such a test as
proof
of intelligence. The problem is that others may see such nonsense as
your
trying to spoil the test as validation of the test itself, which I
object to.
> My desires parallel no such tangent.
Your ends don't justify the means.
It makes perfect sense. You're overthinking it.
I'm simply doing this for the sake of entertainment. And if I can make
fun of the Mega Test and those who consider it legitimate by solving
trivial problems, which are somewhat entertaining in and of
themselves, then I'll do it. The ends do justify the means, because I
have fun doing it and the entire outcome is completely trivial and
speculative as to what exactly is gained. I was trying to agree with
you when I noted that I'm not proving any degree of intelligence. Both
you and I know these tests are not able to "measure" that particular
quality. Instead of overanalyzing what I say and misconstruing the
meaning of it as detrimental to your argument, just take a step back
and accept it as shock value. That's all it is.
Also realize that I haven't done much anything really. I just posted
some answers to the Brain Breaker. No harm done, everybody's fine,
everyone wins.
> How about question 1 on this page?
>
> http://www.eskimo.com/~miyaguch/power.html
How about it? or the others?
OK I'll say 11 for Q1 (and I allowed myself 5 minutes not one day)
--
Siggy played guitar
I can do it in 10. I'm reasonably confident that that's the minimum.
--
Mike Williams
Gentleman of Leisure
Now I've been to the pub I can see that this answer is good.
--
Siggy played guitar
A lot of these have been answered before by this group. I'm just
trying to narrow the scope. Try number 8.
And here is how, specifically:
one 4x4 square
two 2x2 squares at (say) upper left and lower right
six 1x1 squares, two each at upper left, lower left, lower right
one tilted square at upper right
Assumption: Rotations are not considered distinct. (Otherwise, the
answer is trivially 3^6 = 729.)
I reckon it as follows:
1 * 3 = 3 with 6 faces of the same color
1 * 6 = 6 with 5 faces of one color and 1 of another
2 * 6 = 12 with 4 faces of one color and 2 of another
(the 2 are either adjacent or opposite)
2 * 3 = 12 with 3 faces of one color and 3 of another
(of the latter set, either 2 are opposite or they aren't)
2 * 6 = 12 with 4 faces of one color, 1 of another, 1 of the third
(the third color is either adjacent or opposite the second)
3 * 6 = 18 with 3 faces of one color, 2 of another, 1 of the third
(either the 2 are opposite, or the 1 is opposite one of the
2, or the 1 is adjacent to both of the 2)
1 * 1 = 1 with 2 faces of each color and 3 pairs of same-colored
opposite faces
1 * 3 = 3 with 2 faces of each color and exactly 1 pair of same-colored
opposite faces
2 * 1 = 2 with 2 faces of each color and 3 pairs of same-colored
adjacent faces (mirror images)
for a grand total of 69.
The interesting bit is proving that that answer is minimal.
SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
made in the above text. For all I know I might be
drugged or something..
No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT
I can see a solution in 8 I think:
one 4x4 square
three 2x2 square
three 1x1 square
one (diagonal) square
Regards,
Mike.
I don't think that will be possible, as I can do it in nine:
+-------+
|1111111|
|1111111|
|1111111|
|1111111|
|1111111|
|1111111|
|1111111|
+-------+
+-+-----+
|1|22222|
|1|22222|
|1|22222|
|1|22222|
|1|22222|
|1+-----|
|1111111|
+-------+
+-+-----+
|1|22222|
+---+222|
|333|222|
|333|222|
|333|222|
+---+---|
|1111111|
+-------+
+-+-----+
|1|22222|
+---+222|
|333|222|
+---+222|
|444|222|
+444|---|
|444|111|
+-------+
+-+-----+
|1|22222|
+---+222|
|333|222|
+---+222|
|5|4|222|
+-+4|---|
|444|111|
+-------+
+-+-----+
|1|22222|
+---+222|
|333|222|
+---+222|
|5|4|222|
+-+4|---|
|6|4|111|
+-------+
+-+-----+
|1|22222|
+---+222|
|333|222|
+---+222|
|5|4|222|
+-+4|-+-|
|6|4|7|1|
+-------+
+-+-+---+
|1|2|888|
+---+888|
|333|888|
+---+---|
|5|4|222|
+-+4|-+-|
|6|4|7|1|
+-------+
with the ninth being the diamond, which won't fit in with this size ASCII art.
Sorry -having actually tried out what I was thinking (instead of just trying
to visualise it in my head) I see I need another 2x2 square, making 9
squares altogether...
Mike.
At least to 25:
abc jkl stu
def mno vwx
ghi pqr yz*
bajmdgpqhirofclktuxwzyv
(missing s and *)
I got 25. I thought 26 might be possible, but it seems less and less
likely.
If there are no novel solutions to this problem, I'd like to try
something like 17. I got 44%, but I am fairly sure I misinterpreted
the directions. Also, I am not particularly skilled at problems
involving probability. I can post my process if it would help.
Whoops, I also missed e and n, but that's easy to fix:
nebajmdgpqhirofclktuxwzyv
Meaning two rectangles 1 unit in height and 2 units long each, and
aligned like so, with no vertical depth dividers in
the middle of either rectangle. The periods are merely indicators to
side length for occasions when there are simultaneous underscores.
Correct my guess if I am wrong.
Please keep working on number 20. The calculations are meticulous, and
I have a feeling I made a mistake somewhere. I re-solved the problem
and got 49% though.
Ok, since things are getting dead here, I'm placing my interest on
number 36. How would you solve this problem? What is the answer?
http://www.eskimo.com/~miyaguch/power.html
Someone please confirm my prior two answers in the quoted text. Thanks.
Well, the way I would find the answers (assuming enough interest) is
one of the
following:
1. For about $200, you can hire a Russian math PhD to solve them for
you.
2. For about $100, you can hire the local rent-a-thug society to beat
the
answers out of the creator. Of course, the latter has the
disadvantages
of being illegal, and the low probability that the thugs would be able
to
discern the correct answers.
Other than that, I tend to disregard this type of puzzle, because the
answer is only the answer the originator thought up, and has no real
validity.
Have fun.
Thanks for the advice. Does the math PhD have to be Russian? Maybe I
should just hire the thugs. =P
Ah. In another thread I just pointed out that the analogies you
posted there came from the Mega test. Which I now gather you knew.
25 is indeed the max. To prove this, classify the cubes as V, E, F,
and C (for the 8 vertex, 12 edge, 6 face, and 1 center cubes).
Between every pair of V's in a path there must be at least 1 F. If a
C is between 2 V's, then there are at least 2 F's between the V's.
There are at most 6 F's in a path. Therefore if the path has no C's
it can have at most 7 V's, whereas if the path has 1 C, it can have at
most 6 V's. Thus every path must either miss a C and a V, or 2 V's.
The main ones I am concerned with now, other than the analogies you
posted about earlier, are 36 from the power test, the probability
questions (simply because I hate them, I am fairly sure I have the
correct solutions), and of course, the one about the 3
interpenetrating cubes...
If this thread generated enough interest I was going to post all of my
proposed solutions so everyone else could verify them and/or fill in
the blanks, but most of the problems just have the groups stumped...