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On 18/10/2021 18:06, leflynn wrote:
> Simple challenge to create a 26 word list where the starting and ending letters are the same, with one word for each letter of the alphabet. Your score is the total number of letters. If you skip a letter, your score for that letter is 7. Can you get under 100 without consulting a dictionary? Let's use the scrabble players' word list.
I tried.
I failed with j, q, u (no, I don't count Ubuntu!), v, and
x, z. That's 42 penalty points right there. Under 100 is 99 max, less 42
is 57.
Use A, I, and O as one-letter words, which means there are 17 words left
to get with 54 letters. Burn 34 for firsts and lasts, leaving 20 letters
/ 17 words. So we need fourteen three-letter words:
bob did eye gig huh mum nun pip tat wow
covers b d e g h m n p t w (and in my view 'gig', 'huh', 'mum' and 'wow'
are dodgy to say the least),
leaving these seven:
c f k l o r s
We'd have to find three-letter words for four of them and four-letter
words for the remainder. I don't see it.
--
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
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