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Math Equation Puzzles

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easy...@zcloud.net

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Dec 17, 2009, 11:56:48 PM12/17/09
to
I have posted a group of Math Equation Puzzles @

www.easysurf.cc/equation/pgrvl6.htm

Identify the numbers that the letters A - H represent.
Use logic and your math skills to find the solution.

Each puzzle can be printed so that you can work on it off line.

How long will it take you to solve the puzzle?

Post you times here.

Mensanator

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Dec 18, 2009, 1:04:34 AM12/18/09
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Quoth the server: 404

g.r...@iit.cnr.it

unread,
Dec 18, 2009, 4:41:19 AM12/18/09
to
On Dec 18, 7:04 am, Mensanator <mensana...@aol.com> wrote:
> On Dec 17, 10:56 pm, easys...@zcloud.net wrote:
>
> > I have posted a group of Math Equation Puzzles @
>
> >www.easysurf.cc/equation/pgrvl6.htm
>

> Quoth the server: 404

Probably the right address is
http://www.easysurf.cc/equation/pgrvl6.htm

g.

easy...@zcloud.net

unread,
Dec 18, 2009, 12:11:32 PM12/18/09
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The url is:

http://www.easysurf.cc/equation/pgrvl6.htm

or

copy the url and paste it on your browser.

Brian Christiansen

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Dec 18, 2009, 1:44:20 PM12/18/09
to

"Mensanator" <mensa...@aol.com> wrote in message
news:a945f8ae-c79b-406f...@r24g2000yqd.googlegroups.com...

Quoth the server: 404

I don't have any real interest in trying to solve it, but when I clicked on
the link, I went right to what I assume is the correct page.

Brian Christiansen


Mensanator

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Dec 18, 2009, 1:54:34 PM12/18/09
to

Ok.

But it's a doddle.

>>> import itertools as it
>>>
>>> n = [3,5,8,13,16,21,29,32]
>>> c = [ m for m in it.permutations(n)]
>>> truth_matrix = []
>>> for cc in c:
truth_matrix.append(cc[7] + cc[5] == cc[3])
truth_matrix.append(cc[0] + cc[7] == cc[5])
truth_matrix.append(cc[3] - cc[1] == cc[0])
truth_matrix.append(cc[2] - cc[4] == cc[6])
truth_matrix.append(cc[6] - cc[3] == cc[7])
truth_matrix.append(cc[1] - cc[5] == cc[4])
if False in truth_matrix:
pass
else:
print(cc)
truth_matrix = []


(5, 16, 32, 21, 3, 13, 29, 8)

Mensanator

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Dec 18, 2009, 2:01:10 PM12/18/09
to
On Dec 18, 12:44 pm, "Brian Christiansen"
<brian_christi...@hotmail.com> wrote:
> "Mensanator" <mensana...@aol.com> wrote in message

I did too, once he corrected the post.

>
> Brian Christiansen

Richard Heathfield

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Dec 19, 2009, 3:15:44 AM12/19/09
to
In
<4fdbc68f-8652-4996...@y24g2000yqb.googlegroups.com>,
easy...@zcloud.net wrote:

It took about 5 seconds to realise that there is no unique solution.
Here is the puzzle:

4 8 10 12 16 18 24 28
B - G = F
B - G = F
D - B = C
E + A = D
B - G = F
F + C = H

One third of these equations are useless duplications, and it is far
from clear why they are there. But it is very clearl that E and A are
used once each, in the same equation, and as terms of an addition,
which is commutative. There is therefore no way to distinguish
between them.

Anyway, I make it:
B = 12, C = 16, D = 28, F = 8, G = 4, H = 24, with A and E sharing 10
and 18.

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
"Usenet is a strange place" - dmr 29 July 1999
Sig line vacant - apply within

The Qurqirish Dragon

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Dec 19, 2009, 8:41:49 AM12/19/09
to
On Dec 19, 3:15 am, Richard Heathfield <r...@see.sig.invalid> wrote:
> In
> <4fdbc68f-8652-4996-add8-f2c767c21...@y24g2000yqb.googlegroups.com>,

Apparently every time you reload the page you get a new set of
equations and values. I'm not going to bother solving multiple sets,
but the set I solved had a unique solution, and no obviously redundant
equations. (I say obviously, because I didn't bother to keep track of
which equations I used to solve the problem, but none were identical
or transformations of others- e.g. A+B=C and C-A=B)

easy...@zcloud.net

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Dec 19, 2009, 8:43:47 PM12/19/09
to
Richard,
You copied the puzzle using
"B - G = F" 3 times.

Below is the correct puzzle.

A + F = E
C - G = B


B - G = F
D - B = C
E + A = D

F + C = H

----------------------------------------------------------------------

Mensanator

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Dec 20, 2009, 12:57:13 AM12/20/09
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On Dec 19, 7:43�pm, easys...@zcloud.net wrote:

Oh, and while you're tryimg to figure out how to post
to Usenet, please don't send me e-mails with invalid
return addresses.

Richard Heathfield

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Dec 20, 2009, 3:21:45 AM12/20/09
to
In
<61e920ad-2780-409b...@d10g2000yqh.googlegroups.com>,
easy...@zcloud.net wrote:

> Richard,
> You copied the puzzle using
> "B - G = F" 3 times.

I copied what was written on the Web page.

> Below is the correct puzzle.
>
> A + F = E
> C - G = B
> B - G = F
> D - B = C
> E + A = D
> F + C = H

I assume you haven't changed the numbers, so they should be:

4 8 10 12 16 18 24 28

E > A, E > F, D > E, D > B, D > C, C > G, H > F

So either D or H is 28.

C = B + G
H = B + G + F
F + G = B => H = 2B

So H can't be 28 because 14 isn't a valid solution. Therefore, D is
28. C is at least 12 (B + G), so H is at least 24. Since it's at most
24, too, it's 24. So F+C=24. They can't be 18 (no 6), 12 (they'd be
equal), or 4 (no 20), so they must be 16 and 8. C is the sum of B and
G, so it can't be as low as 8, so it must be 16, leaving 8 for F. B
and G are 4 and 12 in some order, and A is 8 less than E, so they are
10, 18 respectively. B-G=F, so B > G, so B is 12, and G is 4.

A = 10
B = 12
C = 16
D = 28
E = 18
F = 8
G = 4
H = 24

4 minutes 17 seconds, including typing and coffee-drinking.

Willem

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Dec 20, 2009, 4:04:22 AM12/20/09
to
easy...@zcloud.net wrote:
) Richard,
) You copied the puzzle using
) "B - G = F" 3 times.
)
) Below is the correct puzzle.

<snip>

I get a different puzzle each time I click your link.


SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
made in the above text. For all I know I might be
drugged or something..
No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT

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