Anybody knows what resistor to get to do this discharging (presuming
for a single battery)? Like maybe one of those fat 2watt "square bar"?
I wouldn't use a resistor. I use a lamp (of the voltage rating
of the bateries, of course...). That way you can See when the
batteries are discharged.
brucer
--
(We excersise the `Oz-ian Option')
"I can't give you brains, but I can give you a diploma."
---------------------------
Bruce T. Ritchie "My employer can speak for itself.
Paul Timmerman - Battery Systems Group: Jet Propulsion Laboratory, Pasadena, Ca
you might want to take a look into the rec.video newsgroup, there's a
lot of info on this subject floating around there right now. It would be
to much to repeat everything here. If you can't get to this newsgroup
email me. I'll send you a summary.
--
Volker Soffel National Semiconductor Corporation
vol...@nsc.nsc.com Embedded Control Division Applications
(408) 721-4360 Santa Clara, CA95052
I find a torch bulb most satisfactory for this, for a number of reasons.
1) You can monitor how the discharge is going by the brightness of the
light. When it goes out I leave it for another hour to make sure.
2) As the batteries discharge (voltage accross them drops) the bulb
gets dimmer (cooler) and so the resistance drops allowing the now smaller
voltage accross the battery to safely discharge faster through the bulb.
This is almost as good as constant current discharging.
As for choosing a bulb, anything with the same or higher voltage than the
batterires will work fine. The bigger tha Wattage, the faster the
discharge. The bulb I use is from a large flash light, I dont remember
the power, but it takes about half an hour to completely flatten batteries
that have become too weak for my flash-gun.
SImon Monk.
The value and power rating for the resistor depends on the voltage rating of
your battery. Here's a simple formula for MINIMUM power rating for the
resistor:
square the voltage of the battery and divide it
by the value of the resistor you are using.
For example:
If you have a 1.5 volt AA battery and you are using a 10 ohm resistor
(I'm just picking a value for the resistor because I know that a 10 ohm
resistor is readily available from places like Radio Shack in different power
ratings).
The power rating (in watts) will be (1.5)^2 / 10 = 2.25/10
= 0.225 watts
You'll need a 10 ohm 1/2 watt resistor. One word of caution, NiCad batteries
are designed to produce tremendous amounts of current for very short periods
of time. (The NiCad batteries used in toy cars can produce 100 amps or more
for a fraction of a second). My point is that they will heat up drastically
or explode if they are asked to produce large amounts of current for long
periods of time. I recommend that you double the power rating that the
above formula tells you to use. This will keep you safe. If you do feel the
battery getting very hot (or the resistor) unhook it.
Greg Lukins
gjlu...@uhura.cc.rochester.edu
Karl R. Schimmel
The Wichita State University
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