Sprocket ratios chart

[Yamadoggiedaddy]

Here is a chart I've used:

[Garrett]

Hate to sound like an idiot, but what do all the numbers actually mean???

Thanks!

Yamadoggiedaddy wrote in message <374405C1...@nono.com>...

[djo...@cyberhighway.nospam.net]

On Thu, 20 May 1999 16:39:33 -0700, "Garrett"
<coffman(remove_this_to_mail)@seanet.com> wrote:

>Hate to sound like an idiot, but what do all the numbers actually mean???

In my way of thinking the math in this table is done backwards. Divide
the rear by the front and you end up with the final drive ratio
expressed "front to back".

For example:

52 tooth rear divided by a 13 tooth front = 4:1, (52/13 = 4) the front
sprocket revolves exactly four times for every one time the rear does.

Dividing the other way, (13/52 = 0.25) simply gives you the ratio
expressed as a decimal fraction. For every revolution of the front the
rear will travel 0.25 (1/4) of a revolution.

Six of one , half dozen of the other.....

Please note that fitting a 20 tooth front and a 80 tooth rear (or a
40/120) will yield the same ratio (4:1) but there are physical
limitations we must deal with. That would be one mighty big set of
sprockets and more chain to deal with.

>Thanks!
>

David - 99 KTM 200EXC
Email: djo...@cyberhighway.net
Home of the "The Very Unofficial RMD Page"
http://www.cyberhighway.net/~djones/

[djo...@cyberhighway.nospam.net]

On Fri, 21 May 1999 04:57:41 GMT, djo...@cyberhighway.nospam.net
wrote:

>
>Please note that fitting a 20 tooth front and a 80 tooth rear (or a
>40/120) will yield the same ratio (4:1)

Oops, should read 30/120............. or 40/160

[Yamadoggiedaddy]

I like the numbers to all be less than 1 but I understand your reasoning
so here is the inverse ratios chart.

djo...@cyberhighway.nospam.net wrote:

> On Thu, 20 May 1999 16:39:33 -0700, "Garrett"
> <coffman(remove_this_to_mail)@seanet.com> wrote:
>
> >Hate to sound like an idiot, but what do all the numbers actually
> mean???
>
> In my way of thinking the math in this table is done backwards. Divide
>
> the rear by the front and you end up with the final drive ratio
> expressed "front to back".
>
> For example:
>
> 52 tooth rear divided by a 13 tooth front = 4:1, (52/13 = 4) the front
>
> sprocket revolves exactly four times for every one time the rear does.
>
> Dividing the other way, (13/52 = 0.25) simply gives you the ratio
> expressed as a decimal fraction. For every revolution of the front the
>
> rear will travel 0.25 (1/4) of a revolution.
>
> Six of one , half dozen of the other.....
>

> Please note that fitting a 20 tooth front and a 80 tooth rear (or a

> 40/120) will yield the same ratio (4:1) but there are physical
> limitations we must deal with. That would be one mighty big set of
> sprockets and more chain to deal with.
>
> >Thanks!
> >
>

[djo...@cyberhighway.nospam.net]

On Fri, 21 May 1999 10:13:04 -0400, Yamadoggiedaddy <n...@nono.com>
wrote:

>I like the numbers to all be less than 1 but I understand your reasoning
>so here is the inverse ratios chart.

Thanks, I'll find a spot for it on the RMD page, great reference
chart....

>djo...@cyberhighway.nospam.net wrote:
>

>> In my way of thinking the math in this table is done backwards. Divide
>>

[djo...@cyberhighway.nospam.net]

On Fri, 21 May 1999 15:14:39 GMT, djo...@cyberhighway.nospam.net
wrote:

>On Fri, 21 May 1999 10:13:04 -0400, Yamadoggiedaddy <n...@nono.com>
>wrote:
>
>>I like the numbers to all be less than 1 but I understand your reasoning
>>so here is the inverse ratios chart.
>
>Thanks, I'll find a spot for it on the RMD page, great reference
>chart....

Oops, deleted it by mistake. YammyPuppyPapa could you email it to me?