Some basic doubts about blocking

[Athenethor]

Since i start playing Jyhad ... (A long time ago, in a galaxy far far away....)
I allways seen two different ways of perform and resolve a Block.
- Only one minion can attempt to block, and if that minion could not block, the
action is succesful. I.e. a bleeding minion A (0 stealth)and a blocking minion B
(0 intercept). With this stats, the minion B is declared as Blocker, but minion
A play some stealth, and the minion B could not play intercept, so the action is
succesfull.

- Any number of minions could try a block. I.e. a bleeding minion A (0
stealth), a blocking minion B (0 intercept) and another blocking minion C with a
raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the
minion A plays a +1 stealth. As none of the blocking minion could increase his
intercept, the minion B blocking Fails, but as minion C is ready, C is declared
as new blocker

Wich one of those ways is teh correct one??
Thnaks

[James Coupe]

In message <%7mX6.12809$pb1.4...@www.newsranger.com>, Athenethor
<nos...@newsranger.com> writes

>- Any number of minions could try a block. I.e. a bleeding minion A (0
>stealth), a blocking minion B (0 intercept) and another blocking minion C with a
>raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the
>minion A plays a +1 stealth. As none of the blocking minion could increase his
>intercept, the minion B blocking Fails, but as minion C is ready, C is declared
>as new blocker

This is the correct way.

Remember, of course, that just because a new blocker turns up, A doesn't
reset his stealth.

A still has the +1 stealth he played against B, because that applies to
the entire action.

--
James Coupe PGP Key: 0x5D623D5D
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[Athenethor]

In article <LSfSJADz...@gratiano.zephyr.org.uk>, James Coupe says...

>
>In message <%7mX6.12809$pb1.4...@www.newsranger.com>, Athenethor
><nos...@newsranger.com> writes
>>- Any number of minions could try a block. I.e. a bleeding minion A (0
>>stealth), a blocking minion B (0 intercept) and another blocking minion C with a
>>raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the
>>minion A plays a +1 stealth. As none of the blocking minion could increase his
>>intercept, the minion B blocking Fails, but as minion C is ready, C is declared
>>as new blocker
>
>This is the correct way.
>
>Remember, of course, that just because a new blocker turns up, A doesn't
>reset his stealth.
>
>A still has the +1 stealth he played against B, because that applies to
>the entire action.
>

First, thanks for the answer, and now, another question:
I think that the same could be applied to cards like Form of Mist, Elder
Impersonation ... this card re-open the blocker assignment stage (Form of mist
type) or remove one blocker from the ready list (Elder Imp. type)
Is this correct??

Athenethor

[LSJ]

The latter. [6.2.2.1]

--
LSJ (vte...@white-wolf.com) V:TES Net.Rep for White Wolf, Inc.
Links to revised rulebook, rulings, errata, and tournament rules:
http://www.white-wolf.com/vtes/

[LSJ]

Athenethor wrote:
> I think that the same could be applied to cards like Form of Mist, Elder
> Impersonation ... this card re-open the blocker assignment stage (Form of mist
> type) or remove one blocker from the ready list (Elder Imp. type)
> Is this correct??

Yes.