bid a freak

[Travis Crump]

All NV, you hold AKQJ A A53 AKJ86, IMPs/Swiss teams, RHO deals

Auction 1:
1N(11-14)-X-XX(unspecified 1-suiter)-p;
2C(forced)-X-2H-p;
p-X-p-2S;
p-?

Auction 2:
1D-X-p-1S;
p-?

Feel free to disagree with calls made on your behalf. What do you do
now, and what is your plan? How much of a difference did the auction make?

[Eric Leong]

Partner has at most 2 hcp and you have no comfortable sure way to find
out partner's shape. For all you know partner is S xxxx H xxx D xxx
C xxx but he could also be S xxx H xxxx D xxx C xxx. So I think
bidding 4S is enough. If a spade slam makes it is probably spade split
well and you got a little lucky in the club suit.

Eric Leong

[Adam Beneschan]

On Thursday, November 8, 2012 3:11:48 PM UTC-8, Eric Leong wrote:
> On Nov 8, 2:02 pm, Travis Crump <pretz...@techhouse.org> wrote:
>
> > All NV, you hold AKQJ A A53 AKJ86, IMPs/Swiss teams, RHO deals

>

> Partner has at most 2 hcp and you have no comfortable sure way to find
> out partner's shape. For all you know partner is S xxxx H xxx D xxx
> C xxx but he could also be S xxx H xxxx D xxx C xxx. So I think
> bidding 4S is enough. If a spade slam makes it is probably spade split
> well and you got a little lucky in the club suit.

Since partner most likely won't have a high card as a hand entry, I wouldn't want to be in a spade slam unless partner has at most two diamonds--then (assuming partner really does have four spades and they break) I can ruff a diamond and hope the club finesse is on. But like you said, I don't know how to find out what I need to know about partner's shape.

-- Adam