Keno Mathematicians Needed for Ontario Canada
Lotto Hack Jack
Lottery Corporation draws 20 numbers out of 70 every night. Prizes are paid
on a $1, $2, $5, or $10 wager, for correctly picking 2 of 2, 3 of 3, 4 of 4,
5 of 5, 6 of 6, 7 of 7, 8 of 8, 9 of 9, and 10 of 10 numbers out of 20
numbers drawn. The odds are astronomical when trying to pick correctly a 10
out of 10 win, even though 20 numbers are drawn. It seems the lower tiers of
3 of 3, and 4 of 4 are attainable often enough to make a little money, even
though the Lottery Corporation made the payouts low enough to discourage
players like me. If mathematics formulae, tables, full wheels and
abbreviated wheels are used, you still have to be good at picking some key
numbers or power numbers to come out ahead. The playing field is large, but
I'm attracted to the idea that 20 numbers are drawn instead of 5, 6, or 7,
as in many big lotteries. Our Keno allows for us to play the game as a pick
2, 3, 4, 5, 6, 7, 8, 9, or 10 number lottery game, as I'm sure most Keno
games allow for. Out of 70 numbers, I've noticed that, more often then not,
about 10 of the chosen numbers are values between 1 and 35, and the rest are
drawn within the number range of 35 to 70. I would like to play this Keno
game as a Pick 3, Pick 4, Pick 5, or Pick 6 game, because picking 7, 8, 9,
or 10 numbers is too mind- boggling. Can you mathematicians figure out if
it's worth playing a Pick 4 out of 4 game within this Keno Lottery, and
calculate if there is a possible high percentage win guarantee of 4 numbers
correct out of 4 numbers which the wheel would pick, if 10 numbers are drawn
out of a pool of 35 numbers? ( That's only half of the numbers drawn from
only half of the total number pool in our Keno game ). A $1.00 Canadian
wager on a 4 of 4 win returns $100.00 tax-free Canadian dollars, a 5 of 5
win returns $250.00 tax-free dollars, and a 6 of 6 win returns $1,000.00
tax-free Canadian dollars on a $1.00 wager. The 3 of 3 win brings only
$25.00, but if you wager $100.00 and get good at picking 3 of 3 numbers out
of 20 numbers drawn in a playing field of 70 numbers, that's $2,500.00
tax-free Canadian dollars. Have any of you approached any Keno Lottery games
from this vantage point? Are any of you familiar with any revealing websites
or software that would help me enhance or experiment with my way of looking
at the Keno scenario which I have presented? Thanks in advance for your
collective thoughts.
Jack
Richard McTavish
One more, & the payout would have been $25,000.
I occasionally play 5 picks for $250 payout(match all 5) or 8 picks for 25,000
payout(match all 8) (all $1.00 wagers).
> Out of 70 numbers, I've noticed that, more often then not,
> about 10 of the chosen numbers are values between 1 and 35, and the rest are
> drawn within the number range of 35 to 70.
I have noticed that as well. However, just when you think you have it figured
out, it will bite you where it hurts.
I think the best strategy for Ontario Keno is to pick some good combinations,
stick with them long-term, and play every day.
Also, try for smaller prizes, 4-pick($100) or 5-pick($250).
I'm not into wheelies, so I can't help you there.
My software doesn't do wheels, but it does have the Ontario Keno Database. Can
perform various analysis functions.
Just note that my software requires the operating system NextStep 3.3 for Intel
to be installed.
The software can be downloaded free of charge from the following
directory:
ftp://next-ftp.peak.org/pub/next/submissions/
mac
and just keep betting till i lose or have reached amount
where i break even, then i up my wager to next tier.,
ie i start with spot, and after 12 bets, if i havnt won $12 i up it too spot
3 where i jeep betting till i either win $32,. or get to losing $32.
it worked well , but ive had arun of bad luck. im upto spot 6, and have
lost around $600
i can keep playing spot 6 till i giet to $1300 down then i got to raise to
spot 7, and i fear any chance of winning in this life time.
but on a brighter note if i win now, i can go back to spot 2 and start off
again, pocketting winnings,. and restarting my loss count from $1
i have down that lots on lower prizes, and 1 $120 win
well thats my game plan,
and heres a lotto and keno odds calculator i knocked up in excel , you will
need excel to use it,. but it should run thru a browser
http://savagegoose.web1000.com/lottoodds.xls
you should be able to type in 70 balls, we use 80 out here
Lotto Hack Jack <ri...@mnsi.net> wrote in message
news:aqrd7...@enews3.newsguy.com...
Thunder Child
Richard McTavish wrote:
>
> I got 7 out of 8 once, for a $200 payout.
> One more, & the payout would have been $25,000.
> I occasionally play 5 picks for $250 payout(match all 5) or 8 picks for 25,000
> payout(match all 8) (all $1.00 wagers).
>
> > Out of 70 numbers, I've noticed that, more often then not,
> > about 10 of the chosen numbers are values between 1 and 35, and the rest are
> > drawn within the number range of 35 to 70.
>
er.. for what it worth TC is not a keno math person... but Richard is
right...
here's my tupence h'penny (two cents for you US folk).
20 numbers picked
10 in 1-35 the rest ( the other 10) =
10 in 35-70.
Sounds the same as odd numbers versus even.
I have these basic rules for any sized lottery / keno...
1) Reduce the field of play (don't care how.... just do it)
Let us suppose you eliminate 10 numbers leaving 60 numbers.
At worst case 10 of the 20 picked numbers happen to be the 10 you
elimates. ( well that's too bad something to do with karma).
So after having elimated 10 numbers you are left with 60.
rule 2
2) Divide numbers into manageable subsets.
divide the 60 numbers into 3 sets of 20 numbers for example.
Now given that the 10 you elimated haad captured lets say 5 of the 20
numbers that leaves 15 numbers for your larger set of 60 numbers. These
15 numbers can fall anywhere in your 60 but your 60 had been divided
into 3 subsets of 20 numbers each.
At this stage anything can happen.. but lets say that one of your subset
should capture a healthy 5 numbers.
At this point wheeling helps somewhat but filtering the numbers finer by
using another common event also helps retain certain guarantees.
so a wheel like 4 if 5 in 20 should work well and if your subset of 20
has more than 5 which is also common... then you could be looking at a
profitable pasttime....
That is to say that you have a group of 20 numbers that should most keno
draws capture 5 numbers sometime more sometimes less.... but it will
happen!!!
You see it not a case of running after the numbers but more of setting a
trap and then waiting for the numbers to fall into it...
i.e UK Lotto.
The old board layout had 5 columns.
I designed several systems that completed ignored the 5th column...(come
what may)
Every other week sometimes more sometimes less all the numbers are
captured in the first 4 columns.
Every time this event occurs is the only time any one of the systems
would actually capture the jackpot. Other times smaller prizes keeps the
interst up. Some of the systems designed use only 3 columns thus
eliminating 20 numbers from 49 in one swoop. Reason for eliminating the
columns.. well there is none... now the frequency of capturing all 6
numbers if reduced but when the event occurs your odds are drastically
reduced from 1 in 14 million (c) to a region of approximately 200,000.
and so.. to summise every other nth week your odds of winning the
jackpot are 1 in x according to your chosen criteria.
hope this helps...