Does this make sense and does anyone see potential in
this method?
Thanks. Robert Perkis / http://www.lotto-logix.com/
It talks about using a "delta" of one (1) which it claims (and I'm not
disputing) is a common feature from within lottery drawings, where you place
this "1" in your picks would cover any 2 numbers.
I see no advantage here but there is another way of looking at it.......
I see the first number in the sequence is the only number 'not' a "delta", why
not just cover the delta's if you want to play this way? i.e.
2 4 6 1 9
Not only are you playing a (sorta) pick 5 to cover the selection of 6 but also a
sliding cover up or down the pool as required, the above would cover these
6numbers
1 3 7 13 14 23
2 4 8 14 15 24
and so on up to...
31 33 39 40 49
Covers 31blocks of your chosen 5 delta's.
The higher you pick the delta's the less over all picks you get to juggle with.
Just another of me brain tickling teasers, :)
gARY
--
"Robert Perkis" <rob...@icdus.com> wrote
Scott
Yes and no... I did some simulation when I first saw that page, and decided
to only use the deltas representing the range between the actual numbers...
Andy
From: 1, 8, 9, 16, 22, 27, 36
I would get:
8-1=7
9-8=1
16-9=7
22-16=6
27-22=5
36-27=9
I use it as a filter during reduction, but it can also be used to make a
limited prediction...
n=delta
(49-5n)-choose-6 minus (49-5(n+1))-choose-6
-------------------------------------------
49-choose-6
This gives us the following table.
delta p(min delta) p(as dec) 1/p
--------------------------------------------
0 6924764 /13983816 0.495198449 2.02
1 3796429 /13983816 0.271487339 3.68
2 1917719 /13983816 0.137138461 7.29
3 869884 /13983816 0.062206482 16.08
4 340424 /13983816 0.024344142 41.08
5 107464 /13983816 0.007684884 130.13
6 24129 /13983816 0.001725495 579.54
7 2919 /13983816 0.000208741 4790.62
Please note that n=0 for the discussion I've seen here means delta of 1
The problem is that you don't know what the smallest number drawn is going
to be and you don't know what the span between each number in ascending
order will be. This would be like taking 15 #'s and wheeling them into
combinations of 5 if 5.
A 5 if 5 using 15 numbers is 3003 combinations in ascending order now I
don't know this one but if you take each 5# combination and arranged then
into every sequence possible and multiply that by 3003, well you get the
picture.
Below is an example using 7 recent draws from the Oh 6/49.
7 recent Oh 6/49 draws
5/4 26 29 30 34 37 49 14
5/8 7 16 17 29 30 38 42
5/11 5 20 36 40 41 45 37
5/15 1 7 18 22 30 35 5
5/18 4 17 28 41 42 47 18
5/22 9 18 21 22 24 31 23
5/25 19 22 29 30 33 45 42
In the next set of numbers the 1st # is the first # of each of the 7 draws
above
the lowest number drawn.
The #'s after that are the span #'s or "Deltas" for the 7 draws above.
If you take the first or lowest number and add the span number to it you
will have the 2nd number of the drawing - 26+03=29, 29+01=30, 30+04=34
and so on.
1st# #Span
26 03 01 04 03 12
07 09 01 12 01 08
05 15 16 04 01 04
01 06 11 04 08 05
04 13 11 13 01 05
09 09 03 01 02 07
19 03 07 01 03 12
The next chart shows the spans or deltas values from 1-15.
The 1st # being the span value and the next 5#'s being the
amount of times occurring in each position.
Position meaning p1-p2, p2-p3, p3-p4, p4-p5, p5-p6.
The last number is the total span value or delta occurrences.
This is based on the last 40 drawings of the Oh 6/49
Span Occurrence Total value
Value per position occurrence
1 02 08 08 08 03 29
2 03 03 05 03 05 19
3 06 03 02 05 04 20
4 04 03 08 04 03 22
5 02 02 02 04 05 15
6 05 05 02 03 03 18
7 01 02 02 02 05 12
8 02 04 03 01 03 13
9 03 01 01 01 02 08
10 03 01 01 01 01 07
11 01 03 00 01 00 05
12 01 01 02 02 02 08
13 04 01 02 01 01 09
14 00 00 01 00 00 01
15 01 01 00 01 00 03
As the span values get higher the occurrence gets lower.
The span between numbers can go into the high 20's, the highest span in the
last 40 drawings of the Oh 6/49 was 29. The average span for a 6/49 is
6-7 between all 6 positions but you wouldn't want to play a span of 6 or 7
between every number in your combinations, that's not how the numbers are
drawn.
In a 6/49 the avg. number by position is 7, 14, 21, 28, 35, 42 but to play
this set of numbers together all the time we would never win a jackpot.
You would want to play a mix of the most common occurring spans and that
still most
likely wouldn't capture a jackpot as you would have to guess what the lowest
number drawn was going to be and what the spans were going to be and if you
did know the first two you still would have to know what order the spans
would appear.
Man, I think I would be better off playing the auto-pick.
Good Luck to all and may all of your deltas be in rivers.
Scott Rudy
>I was out on the web reviewing some lottery site
>links and came across http://www.use4.com/lotto.html
>which talks about converting the 49 numbers to 15
>delta numbers dependent on sequence, predicting from
>within the 15 and than restoring them to combinations.
>
>Does this make sense and does anyone see potential in
>this method?
The sites a bit long winded, I just had a quick
look.
It's well known that about 50% of draws contain 2
balls with a delta of 1 and that this is the most
common delta. I would be very careful though at
using an upper delta less than 15, this could
exclude most of the rollover draws and type 1+2+3
Sean B
>The probability of the smallest delta that can be found in a 6/49 game
>can be calculated by the following equation:
>
>n=delta
>
>(49-5n)-choose-6 minus (49-5(n+1))-choose-6
> -------------------------------------------
> 49-choose-6
>
>This gives us the following table.
>
>delta p(min delta) p(as dec) 1/p
>--------------------------------------------
>0 6924764 /13983816 0.495198449 2.02
>1 3796429 /13983816 0.271487339 3.68
>2 1917719 /13983816 0.137138461 7.29
>3 869884 /13983816 0.062206482 16.08
>4 340424 /13983816 0.024344142 41.08
>5 107464 /13983816 0.007684884 130.13
>6 24129 /13983816 0.001725495 579.54
>7 2919 /13983816 0.000208741 4790.62
>
Nice work Nick, It looks like we will have to make
sure that future entries contain at least 1 delta
of no greater than 5 ;-)
A nice exercise for someone would be to confirm
the above, by checking that their history contains
1.725% of draws with a min. delta of 6
Sean B
Sean B wrote:
> Nick Koutras <tl...@hotmail.com> wrote:
>
> >The probability of the smallest delta that can be found in a 6/49 game
> >can be calculated by the following equation:
> >
> >n=delta
> >
> >(49-5n)-choose-6 minus (49-5(n+1))-choose-6
> > -------------------------------------------
> > 49-choose-6
> >
> >This gives us the following table.
> >
> >delta p(min delta) p(as dec) 1/p
> >--------------------------------------------
> >0 6924764 /13983816 0.495198449 2.02
> >1 3796429 /13983816 0.271487339 3.68
> >2 1917719 /13983816 0.137138461 7.29
> >3 869884 /13983816 0.062206482 16.08
> >4 340424 /13983816 0.024344142 41.08
> >5 107464 /13983816 0.007684884 130.13
> >6 24129 /13983816 0.001725495 579.54
> >7 2919 /13983816 0.000208741 4790.62
> >
>
> Nice work Nick, It looks like we will have to make
> sure that future entries contain at least 1 delta
> of no greater than 5 ;-)
Yes!
But imagine if we "assume" that the smallest delta will be >3
We have eliminated 90% of the combinations!
>
>
> A nice exercise for someone would be to confirm
> the above, by checking that their history contains
> 1.725% of draws with a min. delta of 6
>
> Sean B
>
> >
> >Please note that n=0 for the discussion I've seen here means delta of 1
> >
> >
> >
> >
> >Robert Perkis wrote:
> >
> >> I was out on the web reviewing some lottery site
> >> links and came across http://www.use4.com/lotto.html
> >> which talks about converting the 49 numbers to 15
> >> delta numbers dependent on sequence, predicting from
> >> within the 15 and than restoring them to combinations.
> >>
> >> Does this make sense and does anyone see potential in
> >> this method?
> >>
> >> Thanks. Robert Perkis / http://www.lotto-logix.com/
--
Nick Koutras
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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E-mail : mailto:tl...@hotmail.com
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I went ahead and implemented Deltas into my drawing history routines,
then added deltas to the SCAN output screen. They are interesting
arent they... Besides, aren't deltas almost if not the same as
vectors? The interesting thing to do is to sort the deltas out.
Maybe I can implement a processor to dig into deltas and vectors.
Once I get finished implementing a Sine Wave selector, I will look
into after that.
Andrew
As Scott pointed out, deltas are really gaps which we were talking
about in the pattern thread. It is always interesting the way
numbers can be worked back and forth. Like when they reduce sums
to single digit, hard to say whether it is really any easier to
pick winning numbers from the smaller group and then expand them
back up when we have no better reason for picking within the
smaller group than in the large. Arrrrrrrgh!!! Robert
PcLottery 4.0 is a software that allow to make lines using a command which
specifies deltas ; it calls them "signatures".
The problem comes after you knowing how much different deltas there are in
6/49 lottery as Nick explains and no software tells you which signature will
come next five draws e.g. .
Frank
"Robert Perkis" <rob...@icdus.com> wrote in message
news:3CF87079...@icdus.com...
Scott Rudy
"Andy" <aaa_...@hotmail.com> wrote in message
news:3cf8c60d$0$227$edfa...@dspool01.news.tele.dk...
I know... :)
In my local lottery, almost every draw has a 1, but rarely more than one...
One thing I did notice, is that about 20% of the draws have deltas no larger
than 10, and with all positions either high or low, and following the usual
sine pattern on the sum as well... Now I am looking for a trigger... That
seems to be the hard part!
Andy
Alternatively set a standard and use it consistently that states that all
numbers are read as increases. If you have 27 as a first number in a 0-39
lottery and the next number drawn is 14, the delta would be 27 rather than
13.
Jude <dash...@starpower.net>
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