On Tue, 22 May 2012 09:56:57 -0500, Tim Wescott
<t...@seemywebsite.please> wrote:
>On Tue, 22 May 2012 01:12:32 -0400, Existential Angst wrote:
>
>> Awl --
>>
>> As is proly intuitively clear to most, you break a pencil by applying a
>> bending moment at the center, and <snap>. But it would be REALLY
>> difficult to PULL a pencil apart, or crush it.
>>
>> Iow, the forces req'd to snap a pencil are small, the forces req'd to
>> pull it apart would be huge.
>>
>> I was wondering what the explanation for this is. And I think it may be
>> as simple as this:
>>
>> Ito of INTERNAL stresses in the pencil, when you simply pull on a
>> pencil, you generate an internal psi in the pencil, which is just total
>> Force divided by the cross sectional area, which if less than the
>> material whatever whatever (section modulus or some shit??, the pencil
>> stays intact.
>>
>> However, when you BEND a pencil, now you are generating torques of r x
>> F, and given the sizable r and F of bending, and the very small r of the
>> pencil for resisting sed Torque, the net F generated internally in the
>> pencil becomes very large, with very high resulting internal psi's,
>> which then exceed the intrinsic strength of the pencil. Think finger in
>> a door jamb... at the HINGE!!!! <ouch>
>
>You've hit the nail on the head.
Just be careful about how you conceive of things like "very high
internal psi's." Nothing "internal" matters much in this case. The
core resistance to compression is very low in the cross-grain
direction with wood. That's why balsa-cored laminates arrange the
balsa with the end grain perpendicular to the surfaces.
This is a basic static-bending matter, and the terms and concepts from
statics are the best way to think about it. Aside from keeping the
compression and tension sides apart at low loads, the wood inside has
little to do with anythng. And EA talks about "resisting said torque."
It doesn't resist torque. It resists tension and compression, almost
all of which is going on at the surface fibers on the tension and
compression sides. You have to convert the torque to values of tension
and compression to get anything meaningful out of that.
The idea of bending strength, which is useful in isotropic materials
like metal, really is a derived concept, which combines the tensile
and compressive strengths of the material with its elastic modulus. It
just makes a confusing mess of equations with wood, because, as the
paper I linked to explains, the strength and stiffness values of wood
vary widely in each direction. And wood is a composite material. The
static strength-of-materials equations are similarly complicated to
those of fiber/resin composites. Cellulose is the fiber; lignin is the
resin.
Shear plays a minute role in this with metal. With wood, it can be an
issue in terms of the shear-delamination of the wood fibers. The
result can be like the difference between a piece of plywood and a
stack of veneers of the same material and thickness. The glued plywood
is much stronger and stiffer. But in simple bending, shear
delamination hardly enters the equation at all. You've typically
exceeded the compression strength of the wood before internal fibers
begin to delaminate.
Nothing is ever simple when you start picking it apart, even a pencil.
d8-)
--
Ed Huntress