Oval Cutter
Moonraker
just can't bring myself to pony up $150 for something I won't use that much.
Any of youse guyses got one laying around you'd like to part with for cheap?
Re-move-me@lg-studios.com Glenn G.
or pony up the $$$...
Regards,
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"Moonraker" <moon...@earthlink.net> wrote in message
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Moonraker
strong suit.
You sketch 'er up and I betcha I can make it. I have piles of scraps of
1/4 and 3/8 Plexi/Lexan and a pretty well equipped shop.
"Glenn G." <Glenn Re-mo...@lg-studios.com> wrote in message
news:3c3d4713$1...@goliath2.newsgroups.com...
Andy T.
then cut it out?
Andy
Moonraker
circumscribe an oval, either.
The only ones I could find were for mat cutters, and they hold razor blades
real well. (They didn't seem to be adaptable to cutting glass or drawing
with a marker) The prices were high enough that stepping on up to one which
holds a glass cutter wasn't illogical...just trying to save a few bux if I
could.
"Andy T." <NEOGL...@webtv.net> wrote in message
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JK
looking for oval shape templates. Here's a challenge for ya..... what's the
formula for the area of an oval?
"Moonraker" <moon...@earthlink.net> wrote in message
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Moonraker
I walked out of Mr. McClelland's plane geometry class and never looked back.
I did find a listing for a mat cutter from Fiskars that will cut an oval
almost 9" on the long dimension. One of my friends has a cabinet shop and
has some designs for woodwooking router jigs that will describe an oval up
to the size of a dining room table. I may have to modify one of those to my
purposes. I just need an adjustable way to draw/cut an oval with a long
dimension of maybe 12" or so.
"JK" <jsi...@optonline.net> wrote in message
news:xUo%7.8437$Lq.6...@news02.optonline.net...
Gray Mountain
Picture the oval in your head, then draw a line through the center, both in
the long direction and the short direction, making 4 equal quadrants. The
long line is "a". The short line is "b". Pi is a constant approximately
equal to 3.1415.
The area of the oval is equal to Pi multiplied by "a" multiplied by "b".
The circumference is approximately equal to 2 multiplied by Pi multiplied by
the square root of the sum of "a" squared plus "b" squared divided by 2.
IMHO, the key to drawing or cutting a good oval lies in being able to slide
evenly from (the center, of course) to the short dimension ("b"/2) to the
long dimension ("a"/2).
Hope this helps.
Re-move-me@lg-studios.com Glenn G.
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"Moonraker" <moon...@earthlink.net> wrote in message
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Re-move-me@lg-studios.com Glenn G.
What is the formula for the area smart guy?
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"JK" <jsi...@optonline.net> wrote in message
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Re-move-me@lg-studios.com Glenn G.
centers for your radius'. It is best to see it. If you can't find a book,
let me know and I will TRY to describe the process. It is real easy once
you see it.
Regards,
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"Moonraker" <moon...@earthlink.net> wrote in message
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Randy Hansen
How about just folding some paper in half. Draw half of the oval desired,
cut it out & unfold!
Just a thought from a complete rookie at pattern making.
Randy Hansen
"Gray Mountain" <graymo...@earthlink.net> wrote in message
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Spehro Pefhany
> I did find a listing for a mat cutter from Fiskars that will cut an oval
> almost 9" on the long dimension. One of my friends has a cabinet shop and
> has some designs for woodwooking router jigs that will describe an oval up
> to the size of a dining room table. I may have to modify one of those to my
> purposes. I just need an adjustable way to draw/cut an oval with a long
> dimension of maybe 12" or so.
Seems to me you can draw an oval with two pegs and a loop of string. (You
put the pencil in the loop of string, keep it taunt, and hold the pencil
perpendicular to the surface you are marking. (One peg gets you a circle).
The distance between the pegs determines how oval it is. It might work
better if you drill a pencil-sized hole through a block of wood so the
pencil would automatically be held perpendicular.
If it would fit on my printer (12" x 22"), though, I'd just use a CAD
program and print it out. Could probably tile a bigger one too.
Best regards,
--
Spehro Pefhany --"it's the network..." "The Journey is the reward"
sp...@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
JK
"Gray Mountain" <graymo...@earthlink.net> wrote in message
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Andy T.
A compass and a ruler? They are quite available and cheap. All you
need...
G^2
Or: Two nails, a work board, a length of string tied into a loop and a
pencil will make just about any size oval you can think of.
Andy
Re-move-me@lg-studios.com Glenn G.
oval. If you don't get the tangent points right, it will still look odd.
Regards,
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"Randy Hansen" <bigrand...@concentric.net> wrote in message
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Moonraker
and the length of the string, I'd be greatful. If I need to make a 9x12
oval, I'd like to be able to do it without 3 hours of trial and error.
"Andy T." <NEOGL...@webtv.net> wrote in message
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Thee Monk
And if you can tell me the formulae for the distance between the two
nails and the length of the string, I'd be greatful. If I need to make a
9x12 oval, I'd like to be able to do it without 3 hours of trial and
error.
Aw gee whiz! For an oval that size, just print out the darn thing. Just
about any program, even simple PageMaker allows you to do that. Easy,
just draw half the oval twice with cross hairs to line both sides up and
print it out. Quicker than the nail/stingy/thingy.
Monk
Moonraker
foiling machines and grinders and bandsaws. ;>)
"Thee Monk" <monke...@webtv.net> wrote in message
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mary
Pi, my brother figures for me, he is the mathematician
and I use that number for the figuring of the fee.
So, I sat and thought just what did I do for ovals and semi-circles such as
for arches.
?
I go to the existing door, or arch, even a circle that is cut into the
house. I take paper, a pencil, and after removing existing glass, sometime
i just leave the glass in and add a quarter of an inch to it. Place the
paper over the opening
take an exacto knife and precisely cut to the margin imperfections included.
I then have a perfect template to use for the opening of the window is to be
constructed. I have witnessed over the years, NO two arches are the same,
even when manufactured. No two door openings have ever been the same. Each
unit constructed fits like a glove and no whittling needs to be done to make
it fit.
I didn't need a fancy tool here either.
Mary
"Moonraker" <moon...@earthlink.net> wrote in message
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Re-move-me@lg-studios.com Glenn G.
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
"mary" <mshe...@midstatesd.net> wrote in message
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mary
template of it.
for the small ones
i confess
i do use a thingie i bought at the art supply store or maybe it was office
max
the oval max name of the product
you put a pencil in the end set two screws: 9 for one size 12 for the other
and draw the oval out
it cost i believe like 10 dollars
i didn't realize we were talking so small
my apology
mary
"Glenn G." <Glenn Re-mo...@lg-studios.com> wrote in message
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Randy Hansen
"Glenn G." <Glenn Re-mo...@lg-studios.com> wrote in message
news:3c3eb421$1...@goliath2.newsgroups.com...
Andy T.
Try it... Half a screwed up oval is only half as bad as a full screwed
up oval. If you don't get the tangent points right, it will still look
odd.
-----------------------------------
Odd? Not sure how it would look odd unless you were looking to get a
specific size. there are short squatty ovals as well as long skinny one.
Nothing odd about those. Years ago, I made a oval piece that was about
6" wide and 60" tall. Long and sleek....
Michele Blank
. Long and sleek....
Mike Firth
which isn't clear from your statement.
An ellipse can be drawn by setting two points (nails in a panel) and
making a loop of string that doesn't stretch much and running a marker
inside the loop held tense against the nails.
A machine for drawing/cutting an ellipse is basically a plus mark shaped
groove in wood or plastic and a bar with two adjustable points and a holder
for a marker/cutter at the end. The distances from the marker/cutter to the
first point and from the first pointer to the second determine the size of
the ellipse. Keeping the points in the grooves of the plus mark takes
practice.
--
Mike Firth
Furnace Glass Web Site/Hot Glass Bits
http:// users.ticnet.com/mikefirth/start.htm (remove space to make link)
"Gray Mountain" <graymo...@earthlink.net> wrote in message
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Spehro Pefhany
> And how does this help him cut a 9"x12" oval???
How about this:
get http://www.speff.com/oval912.pdf
Print it out (make sure "fit to page" is unchecked), and blow it up
25% onto tabloid-size paper at Kinkos or whatever.
Jerry Maske
you the freedom to choose the dimensions you want. The Fletcher-Terry
is very confining in it's dimensions; so as long as you are willing to
put up with that problem and only do ovals that device allows, then you
will be happy.
I use a Toyo oval cutter which is really a circle cutter that has an
adjustable elbow about mid way out. Then, I cut an oval template out of
masonite and use the Toyo to trace along the edge of the masonite
template. Been making ovals this way for years and really like the
process. Of course, I'm limited by the template, but have done some
freehand and that works well also. I do a lot of kiln work with ovals
and need each one to exactly the same as the one before it or I won't
get a good edge fuse.
Good Luck,
Jerry
Moonraker wrote:
>
> I'd like to find an oval cutter. I've seen the Fletcher-Terry one, but I
> just can't bring myself to pony up $150 for something I won't use that much.
>
> Any of youse guyses got one laying around you'd like to part with for cheap?
--
? Angel Antics Glass Crafters ?
Fine Art Glass, Kaleidoscopes and
Tiffany Lamp Reproductions
Jerry & Ann Maske
Rt. 1, Box 3
East Sullivan, Maine 04607
Phone (207) 422-2250
Email angel...@acadia.net
Web site http://www.angelantics.net/
JK
> And if you can tell me the formulae for the distance between the two nails
> and the length of the string, I'd be greatful. If I need to make a 9x12
> oval, I'd like to be able to do it without 3 hours of trial and error.
>
Here's the formula..... draw a 9 x 12 box. Take a piece of string and
the 2 nails.... now take about 2 hours to keep changing the distance between
the nails, and the length of the string, till it looks right.... or ask
"Gray Mountain", he's my idol!!
engelbrecht-wiggans richard
> moon...@earthlink.net (Moonraker) spoke:
>
> And if you can tell me the formulae for the distance between the two
> nails and the length of the string, I'd be greatful. If I need to make a
> 9x12 oval, I'd like to be able to do it without 3 hours of trial and
> error.
For an oval with major axis length A and minor axis length B,
The string should have a length of A.
The distance between the nails should be the square root of
A*A-B*B.
For example, to get a 12"x9" oval, use a string 12" long between
the nails and set the nails sqrt(144-81) = just under 8" apart.
Richard.
Richard Engelbrecht-Wiggans, U of Illinois, Champaign, Illinois
email: epl...@uiuc.edu; (217) 333-1088
Dale & Betty
_loop_ of string = a =12" you end up with a 16" oval. And
reading literally a length of string = a=12" won't go around two
nails spaced 8"
engelbrecht-wiggans richard <epl...@uiuc.edu> wrote in message
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Terry Harper
news:3c410...@corp.newsgroups.com...
> news:Pine.GSO.4.31.020112...@staff2.cso.uiuc.edu
> >
> > The string should have a length of A.
> > The distance between the nails should be the square root of
> > A*A-B*B.
> Sorry Richard, but that ain't agonna work! Even if you have a
> _loop_ of string = a =12" you end up with a 16" oval. And
> reading literally a length of string = a=12" won't go around two
> nails spaced 8"
Think of a circle, where a=b. The pins are coincident. The loop of string
draws a circle of radius a/2.
The other extreme is where b=0, and the oval becomes a straight line, as the
pins are "a" apart.
Anything in between gives you an oval, with a minor axis of "b".
--
Terry Harper
http://www.terry.harper.btinternet.co.uk/
Re-move-me@lg-studios.com Glenn G.
then tile print on any printer and tape it together.
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
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engelbrecht-wiggans richard
> Sorry Richard, but that ain't agonna work! Even if you have a
> _loop_ of string = a =12" you end up with a 16" oval. And
> reading literally a length of string = a=12" won't go around two
> nails spaced 8"
If one end of the string is fastened to one nail, the other end to the
other nail, then the length of string between the two nails should be 12"
in order to get an ellipse with a major axis 12" long.
If you want to use a loop, then the length of the loop should be the
average of the major axis length and the distance between the nails;
a loop about 10" long (20" of string plus knots) and nails right about
8" apart will give a 9x12 ellipse.
Richard E+17
Diana Evans
And how do we figure the square footage of the oval we have
created? Lost on that one. Thanks in advance
Diana
Jim Naylor
<Pine.LNX.4.40.020114...@snoopy.oit.edu>,
Diana Evans <eva...@oit.edu> wrote:
> And how do we figure the square footage of the oval we have
> created? Lost on that one. Thanks in advance
>
> Diana
A = pi * a * b
a & B are semi major and minor axes (like radii)
Jim Naylor
> And how do we figure the square footage of the oval we have
> created? Lost on that one. Thanks in advance
>
> Diana
A = pi * a * b
a & b are semi major and minor axes (like radii)
Chunk Kiesling
the nails. If you use a loop of string around the two nails, you'll need
to add the distance between the nails to the major axis (A) to get the
length of string to make the loop.
Chunk Kiesling
engelbrecht-wiggans richard
I think that someone else gave the formula earlier in this
thread, so I'll use that as an excuse to actually "derive"
the formula:
Mathematically, an ellipse with axes of length a and b can be
viewed as a circle of diameter b that has been stretched (in a
linear way) by a factor of a/b in one direction. A circle
with diameter b has a radius of b/2 and therefore an area of
pi*(b/2)*(b/2). So, the area of an ellipse with axes of length
a and b is (pi*(b/2)*(b/2))*(a/b) which simplifies to pi*a*b/4.
Richard E+17
Chunk Kiesling
Here's a picture of showing what to type in for formulas in an excell
spreadsheet.
http://www.ticon.net/~chunk/glass/oval.jpg
Just change the values in B1 and B2 to whatever you want. If using
inches, Format B3 and B4 for fractions(sixteenths) to make measurements
easy.
Save the spreadsheet and call it up whenever you have a new oval to
draw.
Other applications may use slightly different formulas.
If anyone wants the actual spreadsheet, email me and I'll attatch it to
return email.
Chunk Kiesling
Diana Evans
Thanks.
Diana Evans
Thanks!!
Re-move-me@lg-studios.com Glenn G.
lead or foil line you have. You can enter a price per unit and it will
calculate the cost of your piece (even has a scrap factor you can enter).
G^2
--
"Never argue with an idiot. They drag you down to their level then beat you
with experience".
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