On Friday, December 16, 2022 at 5:57:23 PM UTC-5, Eric Bick (DY) wrote:
> Interesting metallurgical question. This is a technique used in industry to fit parts together - cryogenic shrinking of the insert rather than heating the part the insert goes into to expand it. References I found say that steel (unspecified alloy) shrinks about 0.2% at cryogenic (liquid nitrogen) temps. Doing some simple math, a 1.5" diameter pin would shrink about 0.003" (3 mils, ~0.08 mm) in diameter. However, you have to know the alloy of the rod. There are cryogenic steels (used in Arctic climes) that do not become brittle. Many steel alloys do become brittle at liquid N temps (recover to normal when warmed), so care must be used not to impact them or they will shatter. We could calculate the time it takes for the rod to warm to 0 C, which would tell you how fast you'd have to be, but I'll leave that exercise to the reader.
>
> Of course, to do this, you'd want the pin holes in the spars to be exactly lined up (OK, you could be off by about 1.5 mil (0.04 mm), but then you'd be able to put the pins in without cryogenically shrinking them - and for a lot less hassle and cost. Of course, who knows whether I did the math right? Fun question.
In most modern gliders, the pin(s) get inserted into brass or bronze bushings, which are somehow connected to the spar stubs. The heat transfer into the cryogenically cooled pins will cause these bushings to shrink, too. By how much would depend on their geometry but shrink they will. I am not a fiberglass/Carbon expert but thermally stressing that joint repeatedly can't be good. Also, unless you do that cryogenic exercise in a desert environment with single digit humidity levels, you will have a nice coating of water ice on the pin's surface very quickly.
Nice thought, though ....
Uli
'AS'