In order to create the device in the database manager I selected a 10 pin
"through-hole" device. The "radius" of a 9-pin miniature socket is
approximately 380 mils, thus the circumference of a circle about the radius
is roughly 2400 mils.
Draw a circle with "anchor" at 0,0 and diameter of 760 mils (i.e. a chord
from 0,0 to 760, 760) Set the default pad size to 235 mils (with a 52 mil
diam drill) and decorate the circle with the pads, #0 to #9. Eliminate the
index pad at position 0,0. Each of the pin sockets can then be reduced to a
convenient size -- 120 mils or so.
** I just measured two 9 pin ceramic sockets in my stock.
Type 1 is a PCB style with a circle diameter of 20mm or 787 thou.
Type 2 is the common wire loop style with a circle diameter of 18 mm or 708
thou.
The pins of a tube are set on a diameter of 12mm or 472 thou.
Its all over the place.
........... Phil
http://71.253.3.106:808/~tesla/B9A.jpg
Hope this helps. Its not my drawing so there no guarantee :)
Adam