how to create default prefix with only colon with rdflib?

[wqp.g...@gmail.com]

Dear community,

How can I create default prefix with only colon with rdflib?

For instance, I hope to have:

@prefix : <https://xxx> .

<yyy>
rdf:type :fff ;
rdfs:label "example" .

Thanks!

[Nicholas Car]

DEFAULT = rdflib.Namespace('http://example.org/')
g.bind('', DEFAULT)

Nick

--
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[Nicholas Car]

Here's a full example:

-----
import rdflib
from rdflib import RDF, URIRef, Literal

g = rdflib.Graph()
SDO = rdflib.Namespace('https://schema.org/')
g.bind('sdo', SDO)

DEFAULT = rdflib.Namespace('http://example.org/')
g.bind('', DEFAULT)

g.add((
URIRef('http://example.org/person/nick'),
RDF.type,
SDO.Person
))

g.add((
URIRef('http://example.org/person/nick'),
SDO.name,
Literal('Nicholas Car')
))

g.add((
DEFAULT.other,
RDF.type,
SDO.Thing
))
-----

print(g.serialize(format='turtle').decode('utf-8'))

prints:
-----
@prefix : <http://example.org/> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
@prefix sdo: <https://schema.org/> .
@prefix xml: <http://www.w3.org/XML/1998/namespace> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .

:other a sdo:Thing .

<http://example.org/person/nick> a sdo:Person ;
sdo:name "Nicholas Car" .
-----


Nick