Error handling in EasyNetQ

[Simon]

Hi Everyone,

If there is any error occurred in the subscribe call back method, should the message caused the error go into the default error queue?

var busControl = RabbitHutch.CreateBus("host=localhost; virtualHost=/; username=user; password=password",

                x => x.Register<IEasyNetQLogger>(_ => new MyLogger()));

busControl.Subscribe<AccountUpdated>("subid",

                message =>

                {

                    throw new EasyNetQException("Message processing exception - look in the default error queue (broker)");

                });

I thought the message should go into the default error queue, but it still sits in the queue and has status of unacked in RabbitMQ.

I am wondering if I miss anything here?

Thanks

Simon

[Karl Nilsson]

Hi,

You may have more luck on the EasyNetQ mailing list [1]. IIRC messages are meant to be re-published to a special EasyNetQ error queue so not sure what is going on there. Perhaps try throwing a difference exception?

[1] https://groups.google.com/forum/#!forum/easynetq

Cheers

Karl

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Karl Nilsson

Staff Software Engineer, Pivotal/RabbitMQ

[Simon]

Hi Karl,

You are right. This is more for EasyNetQ and I will try my luck on EasyNetQ mailing list. Thanks

Regards,

Simon

On Friday, February 17, 2017 at 7:21:05 PM UTC+11, Karl Nilsson wrote:

Hi,

You may have more luck on the EasyNetQ mailing list [1]. IIRC messages are meant to be re-published to a special EasyNetQ error queue so not sure what is going on there. Perhaps try throwing a difference exception?

[1] https://groups.google.com/forum/#!forum/easynetq

Cheers

Karl

On 17 February 2017 at 07:08, Simon <simon...@gmail.com> wrote:

Hi Everyone,

If there is any error occurred in the subscribe call back method, should the message caused the error go into the default error queue?

var busControl = RabbitHutch.CreateBus("host=localhost; virtualHost=/; username=user; password=password",

                x => x.Register<IEasyNetQLogger>(_ => new MyLogger()));

busControl.Subscribe<AccountUpdated>("subid",

                message =>

                {

                    throw new EasyNetQException("Message processing exception - look in the default error queue (broker)");

                });

I thought the message should go into the default error queue, but it still sits in the queue and has status of unacked in RabbitMQ.

I am wondering if I miss anything here?

Thanks

Simon

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