list on return has difference with print

[delibrax]

Hi guys, I have function here :

def arrayBPMFolder(obj):

    for i in obj:

        #print i

        relatives = mc.listRelatives(i, p=True, f=True)

        #print relatives

        for o in relatives:

            objs = o.split('|')[-2]

            print objs

            #return objs

when i printed objs the result is :

bindCyl03CtrlBPM_grp

bindCyl02CtrlBPM_grp

bindCyl01CtrlBPM_grp

bindCylBase01JntBPM_grp

 
but then when i return objs only shown result as bindCyl03CtrlBPM_grp.

any insight? Thanks in advance! :)

[delibrax]

So I need to get return as similar like print results. How to do that?

[Justin Israel]

On Sat, Oct 6, 2018, 3:48 AM delibrax <adien....@gmail.com> wrote:

So I need to get return as similar like print results. How to do that?

You want to build up a list of your results over the course of the loop and then return that. 

def arrayBPMFolder(obj):

    results = [] 

    for i in obj:

        relatives = mc.listRelatives(i, p=True, f=True)

        for o in relatives:
            objs = o.split('|')[-2]

            results += objs

    return results

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[Justin Israel]

On Sat, Oct 6, 2018, 8:05 AM Justin Israel <justin...@gmail.com> wrote:

On Sat, Oct 6, 2018, 3:48 AM delibrax <adien....@gmail.com> wrote:

So I need to get return as similar like print results. How to do that?

You want to build up a list of your results over the course of the loop and then return that. 

def arrayBPMFolder(obj):

    results = [] 

    for i in obj:
        relatives = mc.listRelatives(i, p=True, f=True)

        for o in relatives:
            objs = o.split('|')[-2]
            results += objs

    return results

Sorry. I had a typo. That's what I get for answering with code from my phone ;) 

We want to append a single item to the list each time. Not add a list to a list. 

def arrayBPMFolder(obj):
    results = []

    for i in obj:
        relatives = mc.listRelatives(i, p=True, f=True)

        for o in relatives:
            objs = o.split('|')[-2]

            results.append(objs)

    return results

[delibrax]

Hi Justin,

Solved.. Thank you! :)

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