Query if a mesh is deformed

[Christian Akesson]

Making a utility method to clean out duplicate shape nodes and I want to check if a mesh is being deformed.

Instead of the if not m.listHistory(type='skinCluster'): I would love if there was a way to check if there is any deformer type on the mesh....

______________________________________________

for m in meshes:

# Filter out bound meshes

if not m.listHistory(type='skinCluster'):

shapes = m.getShapes()

for s in shapes:

if s.intermediateObject.get():

delete(s)

rename(m.getShape(), '%sShape' % m.name())

________________________________________________

Thanks,

/Christian

[Viktoras]

If I understand correctly, you want to delete all intermediate shapes that are not a part of deformation chain for current shape(s)? then your method fails even when there is a skin cluster on the mesh - there can be multiple intermediate shapes due to mesh duplication and some of them unused.

Normally an intermediate shape can be discarded if it's not being connected anywhere, so just list all outgoing connections from each intermediate shape and delete it if there's no connections.

--
http://groups.google.com/group/python_inside_maya

-- 
Viktoras
www.neglostyti.com

[Ofer Koren]

you can specify a broader node type - 'deformer':

if m.listHistory(type='deformer'):
...

- Ofer
www.mrbroken.com

> --
> http://groups.google.com/group/python_inside_maya

[stephenkmann]

You can also run. Delete unused deformers and it basically does the same thing.

Not in front of maya but I stole the code out from the file-optimize- scripts.

> --
> http://groups.google.com/group/python_inside_maya
>

--
Sent from my mobile device

[Christian Akesson]

Excellent. Thanks for the input!

/Christian

--

http://groups.google.com/group/python_inside_maya

[Christian Akesson]

Viktoras:

I want to remove the intermediate shape nodes, but only if the mesh is not being deformed by any deformer in which case those are needed (meshNameShapeOrig, sometimes meshNameShapeDeformed when referenced). These intermediate shapes are sometimes retained on the mesh when duplicating or delete history to get rid of deformers. They cause some issues in our pipeline....

Ofer:

The m.listHistory(type='deformer') does not work for me, tried it with a combination of various arguments. Tried on both the shapes and the mesh transform. Am I missing something?

Thanks,

/Christian

> http://groups.google.com/group/python_inside_maya

--
http://groups.google.com/group/python_inside_maya

[Viktoras]

On 2010.11.17 18:04, Christian Akesson wrote:

Viktoras:

I want to remove the intermediate shape nodes, but only if the mesh is not being deformed by any deformer in which case those are needed (meshNameShapeOrig, sometimes meshNameShapeDeformed when referenced). These intermediate shapes are sometimes retained on the mesh when duplicating or delete history to get rid of deformers. They cause some issues in our pipeline....

that's exactly what i said. if you list outgoing connections from a shape, which is marked as intermediate, and it does not connect anywhere (usually garbage shapes won't at all) - you can delete it.

[Christian Akesson]

I guess this could be a way to go:

m.listHistory(type='deformableShape') always returns 1 shape node if there is no active deformer on it and multiple when deformed....
/Christian

[j...@janberger.de]

`can u filter them by checking whether the intermediateObject attribute is set to true?

 

 

Christian Akesson <cake...@dslextreme.com> hat am 17. November 2010 um 17:25 geschrieben:

> --
> http://groups.google.com/group/python_inside_maya

[Christian Akesson]

Gotcha, I misread your original post. Thanks!
/Christian

--

http://groups.google.com/group/python_inside_maya

[Christian Akesson]

Not sure if it is overkill to do both, but this seems to do that trick and get rid of what you want to get rid of regardless if the mesh is deformed or not...

for m in meshes:

if not m.isReferenced():

shapes = m.getShapes()

for s in shapes:

if s.intermediateObject.get():

if not s.listConnections():

delete(s)

rename(m.getShape(), '%sShape' % m.name())

/Christian

[Viktoras]

yep, you need both checks as there can be regular shape with no deformation which you don't want to delete.

On 2010.11.17 20:43, Christian Akesson wrote:

Not sure if it is overkill to do both, but this seems to do that trick and get rid of what you want to get rid of regardless if the mesh is deformed or not...

for m in meshes:

if not m.isReferenced():

shapes = m.getShapes()

for s in shapes:

if s.intermediateObject.get():

if not s.listConnections():

delete(s)

rename(m.getShape(), '%sShape' % m.name())

/Christian

-- 
Viktoras
www.neglostyti.com

[Ofer Koren]

m.listConnections() will list all connections (inputs and outputs).
better use m.outputs() so you check only outgoing connections
(implying this shape is indeed contributing to a deformation chain).
Input connections can exist even when the shape isn't used in a
deformation chain (such as connections to a poly-creation node, a
layer, for example)

- Ofer
www.mrbroken.com

> --
> http://groups.google.com/group/python_inside_maya
>

[Christian Akesson]

Yepp, good point. 

Thanks for the help.

/Christian

> http://groups.google.com/group/python_inside_maya
>

--
http://groups.google.com/group/python_inside_maya