a question about datetime

[贾晓磊]

hi, all:

I have some tried as follows. it works perfect.

>>> import datetime
>>> today = datetime.datetime.now()

>>> today+datetime.timedelta(weeks=1)

datetime.datetime(2012, 1, 16, 11, 52, 8, 33220)

>>> today+datetime.timedelta(days=1)

datetime.datetime(2012, 1, 10, 11, 52, 8, 33220)

>>> help(datetime)

when i run this piece of code, it failed.

>>> today+datetime.timedelta(months=1)

Traceback (most recent call last):

  File "<stdin>", line 1, in <module>

TypeError: 'months' is an invalid keyword argument for this function

I try to read the source code, but find it 

NAME

    datetime - Fast implementation of the datetime type.

FILE

    /usr/lib/python2.6/lib-dynload/datetime.so

In one word, in the method "datetime.timedelta(months=1)", what are the keys in the method?

if i want to know what key can be used in timedelta(), how should i do ?

-- Jia Xiaolei 

[Dmitri Cherniak]

This isn't related to tornado, so you shouldn't send general python questions like that here.

A google search for "time delta months" should lead you here: http://stackoverflow.com/questions/2249956/how-to-get-the-same-day-of-next-month-of-a-given-day-in-python-using-datetime

[贾晓磊]

sorry for the mis-sending！

then, thanks for the url ypu provided.

In fact, I know how to solve handle the delay about months and year. what i want to know is that in "

>>> import datetime

>>> today = datetime.datetime.now()"

how to achieve it.

sorry again for the interrupting!

-- Jia Xiaolei

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