list1.py

[Bleys Andromeda-Focht]

Good day,

 

I have been plugging along on Google's python class and I have encountered my first problem. In the first problem of the list1.py exercise, I can't seem to find the process. For those that have forgotten the requirements:

 

A. match_ends
# Given a list of strings, return the count of the number of
# strings where the string length is 2 or more and the first
# and last chars of the string are the same.
# Note: python does not have a ++ operator, but += works.

 

My current code isn't worth showing, because I have completely re-written it a few times with no success.

 

Also, I am confused on what the += operator does. Thus far I believe that it only adds a value to an existing list.

 

Thank you for your help.

[Robert Mandić]

You just need to loop through the list and when the condition in question is true, increment the count by one - this is where count +=1 will be needed. It's the same as count = count + 1. If you still have problems, I can provide with full solution.

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[Bleys Andromeda-Focht]

Thank you for the timely answer. That really put me on the right path. Can you please take a look at what I've done so far and let me know if I have the right idea? 

 

def match_ends(words):
  i=3
  count=0
  print words
  while i>0:
    a=words.pop(0)
    if len(a)>0:
      if a[0]==a[-1]:
        count=count+1
      else:
        return
 
 
  i=i-1
  return

 

Eventaully I get the following errors:

 Traceback (most recent call last):
  File "C:\Python27\ArcGIS10.1\Lib\site-packages\pythonwin\pywin\framework\scriptutils.py", line 326, in RunScript
    exec codeObject in __main__.__dict__
  File "C:\Users\bfocht\Bleys\Python\Google\basic\list1.py", line 103, in <module>
    main()
  File "C:\Users\bfocht\Bleys\Python\Google\basic\list1.py", line 78, in main
    test(match_ends(['aba', 'xyz', 'aa', 'x', 'bbb']), 3)
  File "C:\Users\bfocht\Bleys\Python\Google\basic\list1.py", line 28, in match_ends
    a=words.pop(0)
IndexError: pop from empty list

[Robert Mandić]

for word in words:

  c = 0

  # length is 2 or more

  if len(word) >= 2:

    # first and last char in the word are the same

    if word[0] == word[-1]:

      c += 1

  return c

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Lp, Robert