babynames exercise

[Yu Li]

Hi,

 

  I am learning python through the google python course and currently work on all the exercises too. for the babyname exercise. I got part A worked well. How ever when I try to run part B. Basically, generate .summary file, I always got an error saying that: invalid mode <'rU'> or filename: 'baby*.html '.

I tried the program in the solution and same thing happened.

 

  The operation system is windows 7 and I am runing it through MS command prompt. I use Notepad ++ for editing. Anyone know what is going on here? Many many thanks.

[Robert Mandič]

Hello,

sorry for late post - had to get my hands on a windows machine with python cause I wasn't certain about my answer but now I am :D

The system doesn't know how to expand wildcard characeter "*" - therefore it's trying to open file named baby*.html.

If you have a linux/bsd/solaris OS available you can try it there and you'll see it works.

--
Lp, Robert

[Yu Li]

Thanks. I posted to another forum and someone suggested me to use glob.glob. it works. Thanks for your reply.

[Robert Mandič]

I see.

In case someone browses this forum in the future:

  import glob

  for arg in args:

    for filename in glob.glob(arg):

      filedata = extract_names(filename)

On Tue, Nov 8, 2011 at 9:13 PM, Yu Li <yul...@gmail.com> wrote:

Thanks. I posted to another forum and someone suggested me to use glob.glob. it works. Thanks for your reply.

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Lp, Robert

[J T Gillich]

Hi, I followed your suggestion below and I can now run the command in windows but it is only creating a summary file for the last file  in the directory. Any idea why?

[Robert Mandić]

​Actually it's creating summary file for every file but it overwrites it for every iteration ... that's how you only see the summary for the last file.​

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Lp, Robert

[J T]

Thanks for the reply. I am not sure how I write it to do every file? I am very new to programming.

[Robert Mandić]

Can u provide us with your code?

[J T]

Here is my code.

#!/usr/bin/python

# Copyright 2010 Google Inc.

# Licensed under the Apache License, Version 2.0

# http://www.apache.org/licenses/LICENSE-2.0

# Google's Python Class

# http://code.google.com/edu/languages/google-python-class/

import sys

import re

   

def extract_names(filename):

   

#+++your code here+++

# LAB(begin solution)

# The list [year, name_and_rank, name_and_rank, ...] we'll eventually return.

    names = []

    

# Open and read the file.

    f = open(filename, 'rU')

    text = f.read()

# Could process the file line-by-line, but regex on the whole text

# at once is even easier.

# Get the year.

    year_match = re.search(r'Popularity\sin\s(\d\d\d\d)', text)

    if not year_match:

# We didn't find a year, so we'll exit with an error message.

        sys.stderr.write('Couldn\'t find the year!\n')

        sys.exit(1)

    year = year_match.group(1)

    names.append(year)

    

# Extract all the data tuples with a findall()

# each tuple is: (rank, boy-name, girl-name)

    tuples = re.findall(r'<td>(\d+)</td><td>(\w+)</td><td>(\w+)</td>', text)

    # print tuples

# Store data into a dict using each name as a key and that

# name's rank number as the value.

# (if the name is already in there, don't add it, since

# this new rank will be bigger than the previous rank).

    names_to_rank =  {}

    for rank_tuple in tuples:

        (rank, boyname, girlname) = rank_tuple  # unpack the tuple into 3 vars

        if boyname not in names_to_rank:

            names_to_rank[boyname] = rank

        if girlname not in names_to_rank:

            names_to_rank[girlname] = rank

    sorted_names = sorted(names_to_rank.keys())

  

    for name in sorted_names:

        names.append(name + " " + names_to_rank[name])

    return names

    

    # LAB(replace solution)

    # return

    # LAB(end solution)

    

    

def main():

   # This command-line parsing code is provided.

   # Make a list of command line arguments, omitting the [0] element

   #which is the script itself.

    args = sys.argv[1:]

    

    if not args:

        print 'usage: [--summaryfile] file [file ...]'

        sys.exit(1)

   # Notice the summary flag and remove it from args if it is present.

    summary = False

    if args[0] == '--summaryfile':

        summary = True

        del args[0]

  # +++your code here+++

  # For each filename, get the names, then either print the text output

  # or write it to a summary file

  # LAB(begin solution

  

    #for filename in args:

        #names = extract_names(filename)

        #text = '\n'.join(names)

    import glob

    for arg in args:

        for filename in glob.glob(arg):

            #print 'filename is', filename

            filedata = extract_names(filename)

            

            

            text = '\n'.join(filedata) + '\n'

            #print 'this is the text', text 

        

  # Make text out of the whole list

        

        if summary:

            outf = open(filename + '.summary', 'w')

            outf.write(text + '\n')

            outf.close()

        else:

            print text

  # LAB(end solution)

if __name__ == '__main__':

    main()

[Robert Mandić]

This is working as intended:

Running:

$ python tst.py --summaryfile baby1990.html baby2002.html

Created:

$ ls -1 *.summary

baby1990.html.summary

baby2002.html.summary