Re: String2.py Exercise help please

[Andy Withers]

b is the position in the string s of the word "bad". Specifically, it gives you the index position of the start of the word. So when you replace it, you need to replace to the end of the word, which is the start position + 3 (because the word "bad" is 3 letters long). 

Hope that makes sense

On Wed, 10 Mar 2021 at 06:52, Jasper Jones <orionthe...@gmail.com> wrote:

I was able to figure most of this one out but the end has something that i'm confused about. At the end where s = s[:n] + 'good' + s[b+3:] i'm confused what b+3 is?? I get that b references b but +3?? Here's the full code:

def not_bad(s):

  n = s.find('not')

  b = s.find('bad')

  if n != -1 and b != -1 and b > n:

    s = s[:n] + 'good' + s[b+3:]

  return s

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