Table.append() error w/ one column

[Ken Walker]

I've been tinkering with Table.append and ran into an error I can't diagnose.

I started with the 'Particle" append example in the documentation here:

https://www.pytables.org/usersguide/libref/structured_storage.html#tables.Table.append

The description defines 5 columns and Table.append() works exactly as documented: 

class Particle(tb.IsDescription):
    name        = tb.StringCol(16, pos=1) # 16-character String
    lati        = tb.IntCol(pos=2) # integer
    longi       = tb.IntCol(pos=3) # integer
    pressure    = tb.Float32Col(pos=4) # float (single-precision)
    temperature = tb.FloatCol(pos=5) # double (double-precision)

When I modified to only define the 'name' column, I get an error.
The same happens when I only define the 'pressure' column (at pos=1)

Table.append seems to work so long as I have 2 or more columns.

Is this a limitation of the Table.append method?

To verify I can append to a table with 1 column, I used the table.row / append method (similar to tutorial 1).

The following code works:

import tables as tb, numpy as np
class Particle(tb.IsDescription):
    name      = tb.StringCol(16)   # 16-character String

h5f = tb.open_file("particle_t1.h5", mode="w", title="Test file")
group1 = h5f.create_group("/", 'detector1', 'Detector1 information')
table1 = h5f.create_table(group1, 'readout1', Particle, "Readout example")
particle = table1.row
for i in range(3):
    particle['name']  = 'Particle: %6d' % (i)
    particle.append()

table1.flush()

for x in table1.iterrows() :
  print (x['name'])

h5f.close()

The following code gives an error when appending to table1:

import tables as tb
class Particle(tb.IsDescription):
    name        = tb.StringCol(16, pos=1) # 16-character String

h5f  = tb.open_file('append_t1.h5', mode='w')
group1 = h5f.create_group("/", 'detector1', 'Detector1 information')
table1 = h5f.create_table(group1, 'readout1', Particle, "A table")

# Append several rows in only one call
table1.append([("Particle:     10"),
               ("Particle:     11"),
               ("Particle:     12")])

for x in table1.iterrows():
  print (x['name'])

h5f.close()

Am I missing something?

Thanks.

[Francesc Alted]

Hi Ken,

Yes, to create an actual tuple, you missed the comma after the string (e.g. ("Particle:     10",)).  After fixing this in your second example, this is the output I am getting:

b'Particle:     10'

b'Particle:     11'

b'Particle:     12'

Cheers

Francesc

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Francesc Alted

[Ken Walker]

That's embarrassing. LOL @ me

Thanks for the quick response.