pyftpdlib in thread -> how to quit?

[kos...@gmail.com]

Hi, 

1. amazing work with pyftpdlib :) 

2. I have this small issue -> 

I have a special server (3D models remote rendering). It has pyftpdlib built-in for certain reasons. But I need my server no to hang at "ftp_server.server_forever()". I solved this by creating a Ftp server class like this:

class RenderServerFTP(ftpserver.FTPServer, Thread):

    '''

    classdocs

    '''

    def __init__(self):

       

        

        Thread.__init__(self)

        self.authorizer = ftpserver.DummyAuthorizer()

        try:

            self.authorizer.add_user#### BLA BLA

        except ValueError,e:

            Logger.warn(self.__class__.__name__ + " : Error starting FTP server, creating dir for storing models")

            try:

                os.makedirs(join(expanduser("~"), ".arhell"))

            except OSError,e:

                pass

            os.makedirs(join(expanduser("~"), ".arhell", "models"))

            self.authorizer.add_user# BLA BLA BLA

        self.handler = ftpserver.FTPHandler

        self.handler.authorizer = self.authorizer

        ftpserver.FTPServer.__init__(self, ("0.0.0.0", 15021), self.handler)

        

    def run(self):

        self.serve_forever()

=> so it is a thread that doesnt hang. BUT how do I stop the server??? Calling close_all() or close() from a different Thread (3D render server) causes an error:

Shutting down FTP server

 Exception in thread Thread-1:

 Traceback (most recent call last):

   File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 530, in __bootstrap_inner

     self.run()

   File "/Volumes/Kosta_Home/homes/kosta/git/kivyarhellgui/network/RenderServerFTP.py", line 39, in run

     self.serve_forever()

   File "/Library/Python/2.7/site-packages/pyftpdlib/ftpserver.py", line 3751, in serve_forever

     poll_fun(timeout)

   File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/asyncore.py", line 140, in poll

     r, w, e = select.select(r, w, e, timeout)

 error: (9, 'Bad file descriptor')

Any ideas how I can fix this? The FTPserver thread is stuck in its self.run() (self.server_forever()) and is not aware of me trying to quit it from another thread...

thanks

[Giampaolo Rodolà]

Hi there,

you might want to take a look at the thread-based FTP server used in pyftpdlib test suite:

https://code.google.com/p/pyftpdlib/source/browse/tags/release-0.7.0/test/test_ftpd.py#184

It does exactly what you're asking:

- doesn't block on serve_forever()

- can be stopped

- can also be restarted

G.

2012/10/3 <kos...@gmail.com>

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[kos...@gmail.com]

Thank you very much, 

I got to it now finally and that was exactly what I was looking for

Dne středa, 3. října 2012 22:22:17 UTC+2 Giampaolo Rodolà napsal(a):

[karl.ri...@gmail.com]

Could one of you maybe (after this long time) post the relevant code parts because I can't figure them out from the > 3000 lines test case. I guess it would be nice to add this to the tutorial, too (I'd like to file an enhancement request for it or the docs, afterwards).

Best regards,
Kalle

[Giampaolo Rodola']

The test server class is here:

https://code.google.com/p/pyftpdlib/source/browse/trunk/test/test_ftpd.py?spec=svn1264&r=1262#239

For now you can copy and paste it.

There's a plan to move the test server:

https://code.google.com/p/pyftpdlib/issues/detail?id=267

...but I still have to get around to it.

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