Error en WSFEv1.Conectar

[Agustin Milone]

Mariano me sale el siguiente error en esta linea del VB6:

  ok = WSFEv1.Conectar(cache, wsdl, proxy, wrapper, cacert)

utilizo la siguiente URL para produccion:

   wsdl = "https://wsw.afip.gov.ar/wsfev1/service.asmx?wdsl"

 

  

ExpatError: not well-formed (invalid token): line 20, column 64

Traceback (most recent call last):

  File "c:\pyafip\source\utils.py", line 260, in Conectar

    trace = "--trace" in sys.argv)

  File "C:\Python27\lib\site-packages\pysimplesoap\client.py", line 139, in __init__

    self.services = wsdl and self.wsdl_parse(wsdl, debug=trace, cache=cache)

  File "C:\Python27\lib\site-packages\pysimplesoap\client.py", line 459, in wsdl_parse

    wsdl = SimpleXMLElement(xml, namespace=wsdl_uri)

  File "C:\Python27\lib\site-packages\pysimplesoap\simplexml.py", line 180, in __init__

    self.__document = xml.dom.minidom.parseString(text)

  File "C:\Python27\Lib\xml\dom\minidom.py", line 1928, in parseString

    return expatbuilder.parseString(string)

  File "C:\Python27\Lib\xml\dom\expatbuilder.py", line 940, in parseString

    return builder.parseString(string)

  File "C:\Python27\Lib\xml\dom\expatbuilder.py", line 223, in parseString

    parser.Parse(string, True)

ExpatError: not well-formed (invalid token): line 20, column 64

[Agustin Milone]

Ya encontre el problema, esta mal la URL, la correcta es "https://servicios1.afip.gov.ar/wsfev1/service.asmx?WSDL" 

Gracias

Saludos