[pyactiveresource] How to find resource by name

[Matt Fox]

Hi guys,

Thanks for the great library.

I've been banging my head on this issue for hours- how do I find a
resource, given a single attribute? Using the Slicehost API, I'm
trying to grab a single slice knowing the name of the slice.

I've gotten this far:

slice = Slice.find_one('slices.xml', name=slice_name)

But this throws an AttributeError the first time I try to access a
field on slice (bw_out, in particular).

What's the right way to do this?

Let me know if you need more details. I'm new to Python but am
enjoying it so far.

Thanks,
Matt Fox

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[Mark Roach]

Hi, Matt. I don't specifically know the slicehost api, but you shouldn't need to be passing 'slices.xml' to the api.

try:

Slice.find_first(name=slice_name)

[Matt Fox]

Hi Mark,

Running find_first like that results in:

...
  File "/etc/munin/plugins/slice_bandwidth", line 66, in get_slice
    slice = Slice.find_one(name=slice_name)
TypeError: find_one() takes exactly 2 non-keyword arguments (1 given)

Any other ideas?

find_first needs 2 arguments. Here's the contents of the method:

    def find_one(cls, from_, **kwargs):
        """Get a single resource from a specific URL.

        Args:
            from_: The path that resources will be fetched from.
            kwargs: Any keyword arguments for query.
        Returns:
            An ActiveResource object.
        Raises:
            connection.Error: On any communications errors.
            Error: On any other errors.
        """
        return cls._find_one(from_, kwargs)

Thanks,
Matt

[Mark Roach]

Hi again. find_first, not find_one :-)

[Matt Fox]

Completely missed that, obviously. :) Thanks! That's the solution.

Regards,
Matt