Puzzle 1

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Buck Mulligan

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Oct 26, 2004, 6:36:13 AM10/26/04
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Imagine a hollow cube with six chess boards as its six faces. Now if
you internally join all the points of the chess boards on the opposite
faces with parallel straight lines how many internal cubes will you
get? And how many rectangular parallelopiped will be obtained through
this eventually?

vishwas...@gmail.com

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Nov 24, 2004, 1:57:00 AM11/24/04
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I may be missing the point but wouldn't the number of cubes simply be
8^3.

Number of pipes would be 3 * 8^2.

vishwas...@gmail.com

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Nov 24, 2004, 2:19:44 AM11/24/04
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Ok I get it. All size cubes is what you mean.

It would be (1^3 * 8^3) + (2^ 3 * 7^3) +......
The parallelo-piped would be
3 * (1 ^ 2+ 2^ 2 + 3^ 2 + 4^2+ ...8 ^2)

vishwas...@gmail.com

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Nov 24, 2004, 2:31:09 AM11/24/04
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Ok last one it should be

vishwas.man...@gmail.com Nov 23, 11:19 pm show options

From: vishwas.man...@gmail.com
Date: Tue, 23 Nov 2004 23:19:44 -0800
Local: Tues, Nov 23 2004 11:19 pm
Subject: Re: Puzzle 1
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Ok I get it. All size cubes is what you mean.

It would be (8^3 + 7^ 3 +......+ 1 ^ 3)

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