Number of pipes would be 3 * 8^2.
It would be (1^3 * 8^3) + (2^ 3 * 7^3) +......
The parallelo-piped would be
3 * (1 ^ 2+ 2^ 2 + 3^ 2 + 4^2+ ...8 ^2)
vishwas.man...@gmail.com Nov 23, 11:19 pm show options
From: vishwas.man...@gmail.com
Date: Tue, 23 Nov 2004 23:19:44 -0800
Local: Tues, Nov 23 2004 11:19 pm
Subject: Re: Puzzle 1
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Ok I get it. All size cubes is what you mean.
It would be (8^3 + 7^ 3 +......+ 1 ^ 3)