Hi,
I am looking for help with my code.
In my procedure I have psychopy and pygame windows as follow:
win = visual.Window(size=[1200, 680], fullscr=False, screen=0, allowGUI=True, allowStencil=False,
monitor='testMonitor', color='black', colorSpace='rgb', units='height')
......................
pygame.init()
............
pygame.quit()
and when after closing the pygame window by pygame.quit the psychopy window (win) is not active and there I have to click the window.
my question is: is there possible to activate by default the psychopy window without an extra click, please?
regards,
tomasz