Now that I'm back from the beach, I have time for some math (yay!). I got 0 for the answer.
Basic logarithmic rules:
1. log(xy) = log(x) + log(y)
2. log(x/y) = log(x) - log(y)
3. log(x^y) = y log(x)
For the first section - log(a^2-10a+25):
1. a^2-10a+25 can be rewritten as (a-5)^2 so it looks like: log((a-5)^2)
For the middle section - 1/2 log(1/(a-5)^3):
1. Based on logarithmic rule #3, this can be rewritten as: log((1/(a-5)^3)^(1/2))
2. I then multiplied the exponent out, so it looks like: log(1/((a-5)^(3/2)))
For the last section - log(sqrt(a-5)):
1. This can be rewritten as log((a-5)^(1/2))
Putting it all together I got: log((a-5)^2) + log(1/((a-5)^(3/2))) - log((a-5)^(1/2))
Based on logarithmic rule #1, I combined the first and second terms by multiplying them:
log((a-5)^2) + log(1/((a-5)^(3/2))) = log[((a-5)^2)/((a-5)^(3/2))]
This then simplifies to: log((a-5)^(1/2)) by subtracting the exponents.
Now I'm left with: log((a-5)^(1/2)) - log((a-5)^(1/2))
Based on logarithmic rule #1, I combined these two terms by dividing them:
log((a-5)^(1/2)) - log((a-5)^(1/2)) = log[((a-5)^(1/2)/((a-5)^(1/2)) = log(1) = 0