Sun 230 km/s orbital speed around Milky Way
Mercury, 0.24 yr orbital period, 47.87 km/s orbital speed
Venus, 0.61 yr orbital period, 35.02 km/s orbital speed
Earth, 1 yr orbital period, 29.78 km/s orbital speed
Moon , 27 days orbit, 1 km/s orbital speed
1st published book
Atom Totality Universe, 8th edition, 2017// A history log book: Atom Totality Series book 8
by Archimedes Plutonium (Author)
This was AP's first published science book.
Advisory: This is a difficult book to read and is AP's research log book of the Atom Totality in 2016-2017. I want to keep it for its history value. AP advises all readers wanting to know the Plutonium Atom Totality theory to go to the 9th edition that is the latest up to date account of this theory. The reason AP wants to keep the 8th edition is because of Historical Value, for in this book, while writing it, caused the discovery of the real electron is the muon of atoms. The real proton of atoms is 840MeV and not the 938MeV that most books claim. The particle discovered by JJ Thomson in 1897 thinking he discovered the electron of atoms was actually the Dirac magnetic monopole at 0.5MeV. This discovery changes every, every science that uses atoms and electricity and magnetism, in other words, every science.
Foreward:
I wrote the 8th edition of Atom Totality and near the end of writing it in 2017, I had my second greatest physics discovery. I learned the real electron of atoms was the muon at 105MeV and not the tiny 0.5MeV particle that J.J.Thomson found in 1897. So I desperately tried to include that discovery in my 8th edition and it is quite plain to see for I tried to write paragraphs after each chapter saying as much. I knew in 2017, that it was a great discovery, changing all the hard sciences, and reframing and restructuring all the hard sciences.
Length: 632 pages
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(V/(i*B))' = L'
(V/(i*B))' = (V'*i*B - V*i' B - V*i*B') / (i*B)^2
L' = (i^2B - B^3- V^2i) / i^2B^2
When we consider i' as being V and V as being B, then we get a B^3 in numerator.
The three Kepler laws are actually just one law-- that the orbit in gravity is a ellipse covers the T^2/a^3 law and covers the law of equal areas swept out in equal time.
We see the T^2/a^3 in the second term B^3/i^2B^2 only it is inverted to be not equal to 3 but inverted to be 1/3. And the reason for the inversion is that in 3D, the volume of a cylinder is 1/3 cone volume.
The actual geometry for gravity is not the ellipse, never the ellipse, but the Oval, for the perihelion cannot equal aphelion, for they equalled each other for the Sun, then the Sun would swallow up the planet if it did not move faster when it stepped in front of Sun's forward motion.
AP
Bodies in parentheses were not known in 1913, when Blagg wrote her paper. Some of the calculated distances in the Saturn and Uranus systems are not very accurate. This is because the low values of constant B in the table above make them very sensitive to the exact form of function f.
PlanetsIn 1945 D. E. Richardson independently arrived at the same conclusion as Blagg, that the progression ratio was not 2, but 1.728:
(Source Wikipedia)
Feynman in FEYNMAN LECTURES ON PHYSICS Volume I page 2-10, 1963
gives the following (my edited) account of the 4 interactions (forces) of
physics with a comparison of relative coupling strengths in the table below:
"There seem to be just four kinds of interaction between particles which , in
the order of decreasing strength, are the strong nuclear interaction,
electromagnetic interactions, electroweak interaction, and gravity. The
photon is coupled to all electromagnetic interactions and the strength of the
interaction is measured by some number which is 1/137. The detailed law of
this coupling is known and is quantum electrodynamics QED. Gravity is coupled
to all energy and this law is also known. Then there is the electroweak
interaction which causes the neutron to disintegrate into proton, electron,
and neutrino. This law is only partly known. The strong nuclear interaction,
the meson-baryon interaction, has a strength of 1 on this scale and the law is
completely unknown, although there are some known rules such as the number
of baryons does not change in any reaction. "
Table 2-3. Elementary Interactions
Coupling Strength* Law
Photon to charged particles ~10 -2 Law known
Gravity to all energy ~10 -40 Law known
radioactive decay ~10 -5 Law partially known
Mesons to baryons ~1 Law unknown (some rules known)
*The strength is a dimensionless measure of the coupling constant involved
in each interaction ( ~ means approximately equal to).
I change some of Feynman's teachings in the table, giving thus : (A)
renaming weak nuclear as radioactivities (R).
AP writes: Actually, Feynman is wrong, in that Atoms never have a nucleus, for the Muon is the electron of Atoms and stuck inside the proton torus doing the Faraday Law, so in truth the table above should have just 3 forces, the Strongest is the EM force itself. Feynman when he wrote his Lectures on Physics never Unified the Forces of Physics, leaving it for AP in 1991 to unify the 4 forces of physics all into the EM force, for the EM force has the ____only perfect particle = the Photon-Light______.
Now in 2022 I received in sci.math a post trying to figure out if it is possible to move Earth out to Mars. I was not going to get involved mathematically in 2022 or 2023 until the data of Didymos and Dimorphos was in. And I am glad I did, because it turns out the math in all of this is super easy, far easier than the below simpleton account by a nonscientist. And personally, I detest any scientist who still thinks in units of joules, ton. All scientists should convert to the only logical units of electron volts, eV, you can still use Newtons but eventually get to eV. When you do that, you show yourself as grown-up and mature in science.
In sci.math.
On Saturday, December 31, 2022 at 1:23:44 AM UTC-6, bwr fml wrote:
> Let's skip most of what you have thought about and get to the real issue:
>
> Approximately how much energy would be needed to move the earth from
> the current position to the position of mars, pretty much ignoring everything else
>
> distance from earth to mars 9.6*10^7 kilometers
>
> gravitational force of the sun on the earth 3.5*10^22 newtons
>
> 9.6*10^7 kilometers * 3.5*10^22 newtons = 3.36*10^33 joules
>
> Note that is assuming the gravitational force does not decrease
> with distance from the sun. To use a decreasing gravitational
> force you will perhaps need to do an integral. But trying to do that
> sounds like it is way beyond what you have demonstrated thus far.
> Using a constant should still give us a reasonable starting approximation.
>
> So that is the energy you need applied directly to the earth.
> But how much energy is that really, is that a LOT or not so much?
> Well, think of something that has a LOT of energy in it
>
> 1 kilogram of tnt = 4.184*10^6 joules
>
> So how many kilograms of tnt are needed to do this
> (IF and ONLY IF we could directly apply all that energy
> in the right direction and do so uniformly)
>
> 3.36*10^33/(4.184*10^6) = 8*10^26 kilograms of tnt
> = 8*10^23 tons of tnt
> = 8*10^17 mega-tons of tnt
>
> So you need just a bit less than a million million million
> metric tons of tnt to move the earth out to mars.
> And you have to convert all that tnt into a nice uniform
> force on the entire earth for the entire trip.
>
> But how much is a million million million tons?
> Is that a lot or not so much? It sounds like it is a lot.
> Well, worldwide food production of the entire earth in a year
> is about 4 mega-tons each year currently.
> And (8*10^17 mega-tons/(4 mega-tons/year)=2*10^17 years.
> So if all the food production currently was magically turned
> into tnt and we did that every year at the current production
> rate then in only 2*10^17 years you would have enough
> tnt to lift the earth from the current orbit to the orbit of mars.
>
> You must check all these calculations very carefully.
Computing if Earth can be Moved to Mars and then Europa.
----------------------------------------------
So a waffler speaks of TNT, chemical energy to Move Earth. A real scientist speaks of atomic energy which is 10^38 More Powerful than chemical energy.
It is chemical energy that moved Dimorphos a "full 33 minutes faster" and Didymos whose orbital motion was 34km/hour changed by 1/(3*10^9).
So, well, the super easy math is that if the impact was a Atomic weapon, the POWER FACTOR is 10^38 greater than the chemical impact. So that 10^38 times 1/(3^10^9) is approximately 10^29 faster movement, provided of course the mass of the spacecraft was a Uranium missile and that the detonation would keep the asteroid intact and moving away at a colossal speed. Here on Earth we can control that by digging the deepest hole possible and detonating the atomic bomb in the hole well. In fact I remember reading how physicists know someone detonated a atomic bomb underground for Earth is jarred out of its orbit a fraction.
Distance from Earth to Mars is 2*10^8 km
Gravity force of Sun on Earth is 3*10^22 Newtons.
How much energy to move Earth to Mars? Is 6*10^33 Newton*meter.
The Atomic Force is 10^38 stronger than chemical force and so we need a singular Atomic Bomb blast into a deep hole where the bomb is lowered and detonated upon reaching its end of hole.
That is enough to eject Earth out of its orbit with the Sun.
As Earth is moving toward Mars, intermittently we need to add more booster blasts in the hole. Here we have astrophysicists and physicists and engineers monitoring the movement of Earth as it peels away from Sun's gravity and heads for Mars. In a metaphor, we have turned Earth, entire Earth into a rocket.
Will the Moon tag along??? I do not know, yet. But have the suspicion that if the astrophysicists and physicists time it precisely of the when the blast takes place that we can keep the Moon alongside Earth as it moves to Mars. I sincerely hope we can save the Moon. For in keeping the Moon alongside us, allows Earth to have 24 hour day and night, without the Moon 1/2 of Earth will be in full sunshine all the time and the other 1/2 of Earth permanent darkness. So yes, we want to keep the Moon. It maybe the case that we have to detonate a atomic blast into a deep hole in the Moon coinciding with Earth Moving-Day.
How much Uranium does Earth contain to make a bomb?
---------------------------------------------------------------------
Uranium is as common as tin or zinc in geology, and the good news on this is that uranium seems mostly to be found in the crust.
The Atomic bomb blasts need to be coordinated with the inner and outer cores of Earth.
-------------------------------------------------------------------------------
This all is great news, for it finally gives humanity a use for Atomic weapons that the entire Planet Earth and all its life benefits, instead of the crazy political goons who only think of killing their neighbors and stealing their land-- Putin's Russia, Netanyahu's Israel genociding Palestinians and stealing their land. Just today, some Israel idiot said Iran was an existential threat, not mentioning the fact that Israel is a genocider and existential threat on Palestinians in West Bank, Gaza, East Jerusalem but the fool Dondolt buys into all of that.
AP
Rutherford deduced the existence of the atomic nucleus through his experiments but he had nothing to say about how the electrons were arranged around it. In 1912, Niels Bohr joined Rutherford's lab and began his work on a quantum model of the atom.[23]: 19
Max Planck in 1900 and ... had postulated that light energy is emitted or absorbed in discrete amounts known as quanta (singular, quantum). .... When Bohr learned from a friend about Balmer's compact formula for the spectral line data, Bohr quickly realized his model would match it in detail.[48]: 178
Rutherford deduced the existence of the atomic nucleus through his experiments but he had nothing to say about how the electrons were arranged around it. In 1912, Niels Bohr joined Rutherford's lab and began his work on a quantum model of the atom.[23]: 19
Max Planck in 1900 and Albert Einstein in 1905 had postulated that light energy is emitted or absorbed in discrete amounts known as quanta (singular, quantum). This led to a series of atomic models with some quantum aspects, such as that of Arthur Erich Haas in 1910[23]: 197 and the 1912 John William Nicholson atomic model with quantized angular momentum as h/2π.[66][67] Critically, Nicholson successfully reproduces atomic spectral lines, a challenge that Bohr's model would also need to overcome.[51] When Bohr learned from a friend about Balmer's compact formula for the spectral line data, Bohr quickly realized his model would match it in detail.[48]: 178
Alright some calculations using the data from Tsar Bomba with its 2.1 x 10^17 joules yield.
(snipped)
In sci.math.
On Saturday, December 31, 2022 at 1:23:44 AM UTC-6, bwr fml wrote:
> Let's skip most of what you have thought about and get to the real issue:
>
> Approximately how much energy would be needed to move the earth from
> the current position to the position of mars, pretty much ignoring everything else
>
> distance from earth to mars 9.6*10^7 kilometers
>
> gravitational force of the sun on the earth 3.5*10^22 newtons
>
Alright, so Tsar Bomba was yield of 10^17 joules and gravity force of Sun on Earth is 10^22 newtons.We have to multiply Newtons with a distance to turn it into energy.To equilibrate 10^17 with 10^22, I need approximately 1 centimeter.So that Tsar Bomba could push Earth out of orbit towards Mars by 1 centimeter.Now that is not much.And so I need to find out at what distance of a push outward of Earth in its orbit is Earth free of the Sun's pull of gravity. At present, the Earth is locked-into-orbit.But there is a distance perpendicular and away from the orbit where Earth is unlocked from the Sun.Now the best place to detonate the Atomic Bomb for Earth outward push is when the orbit is the furthest distance from the Sun-- aphelion.
A detonation at aphelion concomitant with a detonation on the Moon to pull Earth out of its locked orbit with the Sun.On Sunday, March 22, 2026 at 7:21:36 AM UTC-5 Archimedes Plutonium wrote:Alright some calculations using the data from Tsar Bomba with its 2.1 x 10^17 joules yield.(snipped)In sci.math.
On Saturday, December 31, 2022 at 1:23:44 AM UTC-6, bwr fml wrote:
> Let's skip most of what you have thought about and get to the real issue:
>
> Approximately how much energy would be needed to move the earth from
> the current position to the position of mars, pretty much ignoring everything else
>
> distance from earth to mars 9.6*10^7 kilometers
>
> gravitational force of the sun on the earth 3.5*10^22 newtons
>Alright, so Tsar Bomba was yield of 10^17 joules and gravity force of Sun on Earth is 10^22 newtons.We have to multiply Newtons with a distance to turn it into energy.To equilibrate 10^17 with 10^22, I need approximately 1 centimeter.So that Tsar Bomba could push Earth out of orbit towards Mars by 1 centimeter.Now that is not much.And so I need to find out at what distance of a push outward of Earth in its orbit is Earth free of the Sun's pull of gravity. At present, the Earth is locked-into-orbit.But there is a distance perpendicular and away from the orbit where Earth is unlocked from the Sun.Now the best place to detonate the Atomic Bomb for Earth outward push is when the orbit is the furthest distance from the Sun-- aphelion.I am thinking that if I coordinate a push of the Moon with its tidal forces with the Atomic bomb blast on Earth, that instead of a 1 centimeter push out of orbit can be increased to a full meter out of orbit.And the full meter out of orbit at aphelion causes Earth to be a kilometer out of orbit by the time Earth gets to perihelion that January of the year of the detonation.And I am hopeful that as we do this push out of orbit each successive year, that in a ten year time period, we have pushed Earth free from the Sun's gravity lock and thus Earth is moving in a linear momentum style of course out to Mars, much like a space rocket ship moves from one planet to another planet.
_The most under-rated Physics Experiment in all of human history-------------------------------------------------------------------------------------------------------_The Hertz Experiment of 1887 was a magnificent experiment and still today in 2026 is little understood. What Hertz showed is that a electric current that causes a spark in its circuit is duplicated by radio-wave frequency in a distant circuit, duplicating a current and a spark, although of lower strength than original. This is the basis for radio sets and TV sets._My High School physics textbook PSSC Physics, Haber Schaim, Cross, Dodge, Walter, 3rd edition page 545 shows a picture Figure 23-27 (a) If we walk along beside a moving charge, we see only its Coulomb field. (b) If the charge moves past us, we also see a magnetic field in the same region._In a different High School textbook (at least I think it is High School, 5th edition, PHYSICS : Its Methods and Meanings by Taffel, page 542 writes "This moving combination of electric and magnetic fields regenerating each other as they move forward together at the speed of light constitutes an electromagnetic pulse._Showing a picture where_Figure 28-3. Moving magnetic and electric fields regenerate each other._B moving at velocity c generates E which also moves at velocity c_E moving at velocity c generates B' which also moves at velocity c and is equal to B_AP writes:: you see, I was thinking that it is terribly difficult to explain how a TV station or radio station can convey pictures and voice a distance away. But once you understand the Hertz experiment-- the Radio-waves themselves carry all that information down the antennae to the receiver.
_The author Taffel calls it _____regeneration_______ and I called it simply duplication of what happened at A, happens a distance away at B carried by Radio-pulses._Now, look at the Sun which is an immense ball of electricity and would carry a force via its radiation to form a Ecliptic plane and to send electric current fore and aft of a planet in that magnetic track._Now look at Saturn is an immense ball of electricity and would form a Saturn ecliptic plane of crests and troughs by its radiation that holds ice particles in orbit around Saturn._It is as if we can call the electric currents in a body as the force of gravity itself. As if the Hertz Electromagnetic Radiation in his experiment of 1887 is seeing the Force of Gravity itself._Can we say the Force of Gravity is Radio-Pulses. I think so, only we have to have gravity be 10^38 weaker than the Coulomb force. In the experiments shown on Youtube of the Hertz Experiment, it is __not 10^38 weaker___._But in Feynman's classification of the 3 forces of physics, for Atoms have no nucleus, no strong nuclear force. Comparing the EM force with radioactive force where radioactivity is 1000 times weaker is on the scale of what the YouTube videos replicate the 1887 Hertz Experiment of a spark across a gap._Table 2-3. Elementary Interactions
Coupling Strength* Law
_Photon to charged particles ~10 -2 Law known
_Gravity to all energy ~10 -40 Law known
_radioactive decay ~10 -5 Law partially known
_Mesons to baryons ~1 Law unknown (some rules known)
*The strength is a dimensionless measure of the coupling constant involved
in each interaction ( ~ means approximately equal to).
I change some of Feynman's teachings in the table, giving thus : (A)
renaming weak nuclear as radioactivities (R).
_Let me change a-lot more of Feynman's table for Atoms have no nucleus and the Strong force is nonexistent. The EM force becomes the strongest._And I suspect the Hertz Experiment of 1887 can correct the above table, after doing a Experiment I outline below._The Coulomb constant in its inverse square with distance is actually Permittivity at 8.85*10^-12 F*m^-1._While the Gravity constant is nearly the same numerical value at 6.67*10^-11 m^3*kg^-1*s^-2
This warns us, that since the two constants are about the same, that the strength of gravity versus EM is not that of 10^38 different but rather 10 or 1/10 different on what your perspective is.The Hertz Experiment showed that a transmitter with gap in it causing a spark yields an electric current in a receiver a distance away with a spark being regenerated there.Now I have looked at those Youtube exeriments to duplicate Hertz's 1887 experiment. And honestly, the regenerated current and spark is not a difference of 10^38. No, rather instead the difference looks to me to be about a magnitude of 10 times different, matching the constants are 10 times different.So Old Physics is going to have to open up the case of whether gravity compared to EM force is a difference of 10^38. The 10^38 may well be true but only true as a "myoptic view of gravity versus EM". By that I mean the result of this experiment which I propose.
_AP Experiment on Ice that simulates Saturn Ice Rings
----------------------------------------------------------------------This is far beyond my lab to conduct. Here I need a large professional lab to do this experiment.We take a replica of the Hertz 1887 experiment but modernized. The transmitter and the receiver are placed a specific distance away from each other. Say a meter away. We measure the current in transmitter. And then measure the current regenerated in the receiver. Is it a 10 times difference or is it more????Now, we place a suspended ice particle by string near the gap in Receiver, pretending the transmitter is Saturn and the ice particle a particle in Saturn's rings. The temperature in this experiment should be as cold as what Saturn ring environment is or close enough to it.Of course the ice is a polar dipole moment particle and should react to the transmitter regenerated current.Now Old Physics gravity would say the ice particle is attracted to the Transmitter with a attraction force aimed at the transmitter. But AP says in his gravity-theory, that the ice particle will swing parallel to the transmitter and not towards the transmitter. Much like the Sun shoots radio-pulses aft as a push on Earth and fore as a pull on Earth in the Sun's magnetic track.If I am correct, the ice particle will bend forward parallel to the transmitter and not bend perpendicular towards the transmitter. And the bend should be about 1/10 relative to distance between transmitter and receiver.Now if all of that is true, then the force of gravity parallel to transmitter is 1/10 but we can still have the 10^-38 strength in that the attraction towards the transmitter by the ice particle is this 10^-38 attraction.I am not counting out the 10^38 force strength, just yet. I am looking for another physical experiment that requires the 10^38, but cannot think of one at this moment in time.If the above Experiment is true, then we are certain that Gravity is just radio-waves and that gravity is crests and troughs in Space in which they are magnetic tracks and electric current pushes and pulls plantets in those magnetic tracks.
The aim of Wu's experiment was to determine whether parity is conserved for the weak interaction that governs beta decay. Wigner's mathematical concept of parity conservation, the equivalence of an object or process when the coordinate system is inverted, is equivalent to a mirror reflection followed by a 180° rotation in the plane of the mirror.[5] Cobalt-60 nuclei have spin so the concept of the experiment can be imagined with a spinning ball.[18] A ball spinning in a right-hand rule direction would have a mirror image with a left-hand spin, but this mirror image ball would look identical to an upside down ball spinning according to the right hand rule: after the 180° rotation there would be no physical differences. However, if the spinning ball had a mark on top or bottom, the reflection would no longer look the same. If the emitted electron from decay products of cobalt-60 were being emitted preferentially either along or against the cobalt spin axis direction, this would create a difference analogous to the mark. A difference in emission probability would signify a violation of parity symmetry. As stated by Wu et al.:[1]
The idea can also be described using the properties of vectors. The cobalt-60 nucleus has spin, and spin angular momentum does not change direction under parity. A vector with this property is called an axial vector. Conversely, the direction in which the decay products are emitted is changed under parity and their linear momentum vector is called polar vector. In other words, if in one view the cobalt-60 nuclear spin and the decay product emissions were both in roughly the same direction, then in a mirror image world, they would be in roughly opposite directions, because the emission direction would have been flipped, but the spin direction would not.[19]
Conceptually the experiment is "relatively simple": orient Co60by means of a magnetic field and measure the amount of beta emission directed along or against the direction of the magnetic field.
--- end quoting Wikipedia---
The nonconservation of Parity is a mere reflection that EM laws never obey the Left Hand Rule, always the Right Hand Rule.
AP, King of Science