How to catch a java.util.concurrent.TimeoutException in 2.5

[Sandy Miller]

I am using Play 2.5 and cannot catch a Timeout exception. Here is my code.

    WSRequest request = ws.url(serviceURL)
        .setHeader("Authorization", Application.authorizationHeader())
        .setRequestTimeout(1800000);


    return request.post( postBody ).thenApplyAsync( response -> {
        JsonNode json = response.asJson();

        if ( response.getStatus() == OK || response.getStatus() == CREATED ) {

            return created( json );

        } else if ( response.getStatus() == REQUEST_TIMEOUT ) {

            return internalServerError();

        } else {

            return internalServerError( json );
        }
    } );

I put try and catch around this code but still cannot catch it.

try {

WSRequest request = ws.url(serviceURL)

} catch (Exception e){

}

[Will Sargent]

Can you try using thenApply rather than thenApplyAsync?  That's probably the most direct route.

You may want to use an async timeout i.e.

http://iteratrlearning.com/java9/2016/09/13/java9-timeouts-completablefutures.html

Play 2.6 will have a built in timeout class that will make this easier.

--

Will Sargent

Engineer, Lightbend, Inc.

will.s...@lightbend.com

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[Greg Methvin]

Hi Sandy,

Play's WS client is asynchronous. Instead of throwing the exception directly, the error is returned in a failed CompletionStage.

You could use exceptionally to handle the exception, or use handle/handleAsync instead of thenApplyAsync.

Greg

On Thu, Jan 19, 2017 at 7:12 AM, Sandy Miller <sapm...@gmail.com> wrote:

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Greg Methvin

Tech Lead - Play Framework

Lightbend, Inc.