Play Upload File using Restful API

[Roshan Sharma]

I am new to play and rest. I am trying to implement restful file upload. Someone please provide me basic information regarding how should I request the API and how to upload from backend. What will be the request and how can it be stored in a physical path. 

Thank you in advance.

[Roshan Sharma]

Anyone? Please advice.

[Jason Pearson]

Are you using Java or Scala, and what version?

Java: http://www.playframework.com/documentation/2.1.1/JavaFileUpload

Scala: http://www.playframework.com/documentation/2.1.1/ScalaFileUpload

If you're really new to Play! I would suggest going through the other documentation about controllers, routes, and views to get going before you jump straight into handing multipart form data.

On Wed, Aug 14, 2013 at 10:39 PM, Roshan Sharma <rosh...@gmail.com> wrote:

Anyone? Please advice.

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[Roshan Sharma]

Thank you Jason for reply but I have gone through it. I am using scala 2.10.1. The application is RESTful (I dont have client) and I need to know how to upload and test. For testing I am using Chrome Poster.

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Roshan Sharma

[Jason Pearson]

Sorry for the lack of response, I'm on vacation.  Also what version of Play are you using?

[Roshan Sharma]

Its play 2.1.1

[Puneet Jain]

Hi Roshan,

Did you find the solution to your problem. I need to do the same. Please let me know the solution you found?

Thanks,

Puneet

[Roshan Sharma]

First I converted multipart form data to bytes:

def multipartFormDataAsBytes: BodyParser[MultipartFormData[Option[(Array[Byte], String, String)]]] = parse.multipartFormData(handleFilePartAsByteArray)

  def handleFilePartAsByteArray: BodyParsers.parse.Multipart.PartHandler[MultipartFormData.FilePart[Option[(Array[Byte], String, String)]]] = {

    parse.Multipart.handleFilePart {

      case parse.Multipart.FileInfo(partName, filename, contentType) =>

        Iteratee.fold[Array[Byte], ByteArrayOutputStream](

          new ByteArrayOutputStream()) { (os, data) =>

            os.write(data)

            os

          }.mapDone { os =>

            os.close()

            Some(os.toByteArray, filename, contentType.get)

          }

    }

  }

In my controller method with above parser, I did this:

     val params = request.body.asFormUrlEncoded

    

    request.body.files(0).ref match {

      case Some((data, fileName, contentType)) => {

        //your logic here

     }

      case _ => NotFound

    }

I dont know if its the best way but it was working for me and I didnt want to spend more time on this.