[PATCH] doc: fix description of how to handle possibly negative parameters

1 view
Skip to first unread message

skimo-...@kotnet.org

unread,
Nov 29, 2009, 2:24:41 PM11/29/09
to piplib-de...@googlegroups.com, Paul Feautrier
From: Sven Verdoolaege <sk...@kotnet.org>

Commit 3b332f7 (doc: clarify handling of negative unknowns and parameters)
"clarified" the original description, but the new description implied
that every possbibly negative parameter requires the introduction of
a separate additional parameter, whereas in fact one additional parameter
is sufficient. Revert the description to something that is closer
to the original description.

Unfortunately, the implementation in piplib was based on the "clarified"
description and therefore doubles the number of parameters, whereas
only one extra parameter would do. This should be fixed at some point.

Signed-off-by: Sven Verdoolaege <sk...@kotnet.org>
---
doc/piplib.texi | 35 +++++++++++++++++++++--------------
1 files changed, 21 insertions(+), 14 deletions(-)

diff --git a/doc/piplib.texi b/doc/piplib.texi
index 5b31ded..cc305da 100644
--- a/doc/piplib.texi
+++ b/doc/piplib.texi
@@ -1413,9 +1413,6 @@ As above, we introduce a new unknown @math{f} and the inequality
Since we want to optimize @math{f}, @math{f}
will appear as the first unknown.

-To allow @math{n} (or any other parameter) to become negative,
-we apply the standard trick of replacing @math{n} by @math{n = n' - n''},
-where @math{n'} and @math{n''} are two new parameters, both non-negative.
For handling possibly negative unknows, we add a number @math{G} to each
of the unknowns that ensures that
@tex
@@ -1447,22 +1444,32 @@ $$
@end ifnottex
Hence, @math{G}
is again a big parameter.
+Possibly negative parameters can be handled in a similar way,
+by adding an additional parameter @math{P} to each of the parameters,
+i.e., by considering @math{n' = n + P}. For each value of @math{n},
+there is a pair of non-negative values of @math{n'} and @math{P},
+so any solution that is valid for all non-negative values
+of @math{n'} and @math{P} satisfying the constraints, is also
+valid for all values of @math{n} satisfying the constraints.
+The same additional parameter @math{P} can be used to handle
+all possibly negative parameters, but @math{P} needs to be distinct
+from @math{G} and @math{P} need not be a big parameter.
After replacement of @math{i,j,n} and @math{f} by the new variables
-@math{i',j',n',n''} and @math{f'}, we obtain the set
+@math{G,P,i',j',n'} and @math{f'}, we obtain the set
@tex
$$
\eqalign{ \{\, (f',i',j') \mid
& f' -i' + 2j' - 2 G \geq 0 \, \wedge \cr
- & 4 (n'-n'') -20 \leq i' + j' - 2 G \leq 0 \, \wedge \cr
- & -2 (n'-n'') - 10 \leq i' - j' \leq 2 (n'-n'') + 10 \,\},}
+ & 4 (n'-P) -20 \leq i' + j' - 2 G \leq 0 \, \wedge \cr
+ & -2 (n'-P) - 10 \leq i' - j' \leq 2 (n'-P) + 10 \,\},}
$$
@end tex
@ifnottex
@example
@group
@math{@{(f',i',j') | f' -i' + 2j' - 2 G >= 0,
- 4 (n'-n'') -20 >= i' + j' - 2 G >= 0,
- -2 (n'-n'') - 10 >= i' - j' >= 2 (n'-n'') + 10@}}
+ 4 (n'-P) -20 >= i' + j' - 2 G >= 0,
+ -2 (n'-P) - 10 >= i' - j' >= 2 (n'-P) + 10@}}
@end group
@end example
@end ifnottex
@@ -1471,7 +1478,7 @@ which corresponds to the following input:
@group
( ( Solving MIN(i-2.j) under the following constraints:
Unknowns may be negative.
- Order: f' i' j' constant G n'' n'
+ Order: f' i' j' constant G P n'
)
3 3 5 0 4 1
( #[ 1 -1 2 0 -2 0 0 ]
@@ -1490,7 +1497,7 @@ The result is:
@group
( ( Solving MIN(i-2.j) under the following constraints:
Unknowns may be negative.
- Order: f' i' j' constant G n'' n' -1
+ Order: f' i' j' constant G P n' -1
)
( if #[ 0 -1 1 5]
(list #[ 1 3 -3 -15]
@@ -1505,16 +1512,16 @@ The result is:
which should be read as:
@tex
$$
-\eqalign{(f',i',j') =\; & {\tt if}\; (-n''+n'+5 \geq 0) \cr
- & {\tt then} \; (G+3n''-3n'-15, G+n''-n'-5,G-n''+n'+5) \cr
+\eqalign{(f',i',j') =\; & {\tt if}\; (-P+n'+5 \geq 0) \cr
+ & {\tt then} \; (G+3P-3n'-15, G+P-n'-5,G-P+n'+5) \cr
& {\tt else} \; \bot}
$$
@end tex
@ifnottex
@example
@group
-@math{(f',i',j') = @strong{if} (-n''+n'+5 >= 0)
- @strong{then} (G+3n''-3n'-15, G+n''-n'-5,G-n''+n'+5)
+@math{(f',i',j') = @strong{if} (-P+n'+5 >= 0)
+ @strong{then} (G+3P-3n'-15, G+P-n'-5,G-P+n'+5)
@strong{else} bottom}
@end group
@end example
--
1.6.5.3.171.ge36e

Reply all
Reply to author
Forward
0 new messages