I am looking for some help please in identifying a couple devices used
across an RS422 communications line on a board.
Ther's a photo here ... http://imagebin.ca/view/UJfdCKe.html
One device goes between one of the RS422 comms line and ground and the
second one goes between the other comms line and ground.
They look just like resistors, but obviously are not. They have what looks
like a glass body with painted on rings. A bit like a large 1N4148.
Out of circuit one measures 194 ohm both ways and the other about 35 Meg
ohms both ways. (no fingers)
I'm assuming they are varistors or transient voltage protectors of some
sort, but have no idea on values or where to source a suitable replacement
The board got damp and had a fair bit of corrosion around that area.
Just out of interest, the 2R2 smd's that are visible in the photo are
inductors, not resistors. You'd think manufacturers could come up with some
markings that weren't so potentially confusing.
Thanks, Roger
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Might they be TVS or ESD diodes for noise suppression ?
> Just out of interest, the 2R2 smd's that are visible in the photo are
> inductors, not resistors. You'd think manufacturers could come up
> with some markings that weren't so potentially confusing
Yes, I've got some 3R3 inductors in small SMPS, but they are round,
blue and are obviously inductors. Unlike the 3R6 and 1R0 resistors
right next to them. R is an odd choice. Also, inductor marked 101 is
100uH. But so, I've found, might the inductor marked 100. Or might
be only 10uH, depending on who made it
--------------------------------------------------
From: "ivp" <joeco...@clear.net.nz>
Sent: Thursday, June 10, 2010 12:13 AM
To: "Microcontroller discussion list - Public." <pic...@mit.edu>
Subject: Re: [EE] Need help to ID a part please
>> They look just like resistors, but obviously are not. They have
>> what looks like a glass body with painted on rings. A bit like a
>> large 1N4148
>
> Might they be TVS or ESD diodes for noise suppression ?
TVS or similar sounds like a reasonable bet. Other less likely ideas: they
could be axial capacitors(2300pF?), or maybe a 1N233 diode?
Looks like they are both the same, and the fact you measured different
resistances may mean either one or both is dead or cannot be measured
properly with a multimeter (might be worth applying an increasing voltage
while monitoring current to see how the part reacts). Also, it might be
worth cutting one open to look for a clue.
Assuming you measured this with a normal ohmmeter that puts a volt or less
accross the device, 35Mohm sounds plausible and 194ohm is most likely fried.
I guess they are intended to clamp the lines within some acceptable voltage
of ground. They are probably TVSs. You should be able to replace them with
any TVS with a reasonable rating given whatever common mode range your
circuit has to handle.
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(978) 742-9014. Gold level PIC consultants since 2000.
_
Graphs are for flange temperature and Temperature rise Tjc - junction to
case.
You care about Tja - junction to air.
Data sheet implies max junction temperature is 155 C.
At 25C ambient that's a delta T of 120 C.
TO220 pkg has a nominal Rjcthermal of about 60 C/w.
So at 2W you'd use up that 120 C.
They say 2.5 W so that suggests a slightly better Tjcth of 120/2.5 = 48 C/W.
You can improve that quite a lot with vertical mounting and a very modest
heatsink. Chances are you can fit SOME heatsink here - even if not a
traditional one. Thought followed by common sense design should make quite a
lot of difference.
At 40 C you can have (155-40)/48 =~ 2.4 Watts.
Russell
On 10 June 2010 19:28, Moreira, Luis A <Luis.M...@ccfe.ac.uk> wrote:
>
> Hi All,
> I need to get a resistor to replace a damaged one on a board where is
> used to measure current, it is a 50 mOhm 5W resistor. This is a one off
> job.
> I found this one http://www.farnell.com/datasheets/6367.pdf . Now this
> is a resistor that normally needs a heatsink but I do not have the space
> to fit one hence I would like to use it without it. Looking at the
> graphs given for derating and calculating for 5W dissipation on it, and
> 40 degrees C ambient,
> Assuming you measured this with a normal ohmmeter that puts a volt or less
> accross the device, 35Mohm sounds plausible and 194ohm is most likely
> fried.
Yes, I just used a normal meter. I was convinced that 194ohms was wrong, but
the other one didn't really give me any great clues either.
> I guess they are intended to clamp the lines within some acceptable
> voltage
> of ground.
That was my impression too.
They are probably TVSs. You should be able to replace them with
> any TVS with a reasonable rating given whatever common mode range your
> circuit has to handle.
This is where I am still a little in the dark, because all I have is a
faulty board ... I dont have a circuit or any user manual for any of the
system, or for any of the parameters, other than a legend on the back that
shows it runs on 24v dc. The rest I've had to guess.
Other than not having anything to communicate to the board with, I have
everything else working ... so I'll take a stab at a value, fit a couple
of TVS's, send it back and see what happens.
Thanks to everyone who has replied.
Regards, Roger
-----Original Message-----
From: piclist...@mit.edu [mailto:piclist...@mit.edu] On Behalf
Of RussellMc
Sent: 10 June 2010 12:33
To: Microcontroller discussion list - Public.
Take the TVS that measured open with the ohmmeter and put a 1Kohm resistor
in series with it. Now connect a variable power supply to the combination
and monitor the voltage accross the TVS. At some point the TVS voltage will
stay roughly flat as you increase the power supply voltage. This should
happen the same in both directions, but it's also possible for a TVS to be
half fried and only clamp in one direction. Try both directions therefore.
If you get close to the same answer each way, then that's the voltage
rating. You should be able to replace the busted one with a similar or
slightly bigger size part at the same voltage rating.
Power dissipation is mostly a function of the package, so if the replacement
has the same voltage rating and the same package, then it should be roughly
equivalent. Since one of the existing TVSs blew out, it wouldn't hurt to
replace both with a slightly bigger part, since that should take a little
more energy before frying.
********************************************************************
Embed Inc, Littleton Massachusetts, http://www.embedinc.com/products
(978) 742-9014. Gold level PIC consultants since 2000.
> Take the TVS that measured open with the ohmmeter and put a 1Kohm resistor
> in series with it. Now connect a variable power supply to the combination
> and monitor the voltage accross the TVS. At some point the TVS voltage
> will
> stay roughly flat as you increase the power supply voltage.
Thanks for that suggestion Olin, I went straight out to the w/shop to try it
out.
As frustrating as it is, the device appears open circuit both ways. I fitted
a 1K ohm resistor in series and ran the supply slowly up to 50 volts, and
the voltage across the device went straight up to 50V too!! Tried it the
other way too and same thing.
I hooked up the other one, and that acted just like a 195 ohm resistor, both
ways, so I'm pretty definite that one is dud.
> Power dissipation is mostly a function of the package, so if the
> replacement
> has the same voltage rating and the same package, then it should be
> roughly
> equivalent. Since one of the existing TVSs blew out, it wouldn't hurt to
> replace both with a slightly bigger part, since that should take a little
> more energy before frying.
That sounds pretty much how I normally work when I cant find a circuit or
any documentation to help. I normally get away with it, but thought it was
definitely worth a try asking all you guys.
Thanks again, Roger
:: need to get a resistor to replace a damaged one on a board where is
:::: used to measure current, it is a 50 mOhm 5W resistor.
Have you thought of using a short length of resistance wire - can be
purchased (here locally) at 1.73 ohms per metre.
Colin
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Several strands in parallel would get down to 0.05 ohms and add bulk.
I've done this a couple of times to make medium-power shunts
For example, 13.77 ohm/m nichrome (7.26cm/ohm). 0.05R is only
3.63mm but 10 strands 3.63cm in parallel -> 50mR. Or 20 strands
of 7.26cm
Nichrome or Cuprothal will have published temperature coefficients
that can be used to assess whether changes are significant
Also can get Constantan which has higher resistance per square (per
length at given area) and is almost invariable in resistance with
temperature. Has a commoner name which flees but will return and
Gargoyle knows. Also cheap.
Can rate wattage for whatever temperature rise suits.
Neither solders nicely with standard solders.
R
Obviously a fatter, longer piece is less likely to act as "filament" or
Polystyrene cutter. Teflon or fibreglass can be used to insulate I suppose.
http://en.wikipedia.org/wiki/Constantan
This may *now* mention Eureka (one never knows if someone higher in the
food chain takes exception to an edit)
Can't say I've noticed that with the resistance wire from DSE
(Cuprothal 6R/m) or Electus (Nichrome 13R77/m)
Do the math. At 1.73 ohms/m, you would need 29mm (1.1 inches) to achieve
50mOhms. At 5W that would definitely get hot. You wouldn't want to touch
it. But melting the solder at the ends is a bit melodramatic. A good
fraction of the heat would conduct straight from the wire into the air.
Even if none of it did, each solder joint would have to dissipate only 2.5W,
so 2W or less is a reasonable figure. Again, that's going to get hot, but
well below solder melting temperature. Picture it this way, how far do you
think you'd get trying to solder the wire on with a 2W soldering iron?
You could use two sections of twice the lenth in parallel, but spaced apart
so that they are somewhat separately air cooled. Now you've got a total of
about 4.6 inches of wire and 4 solder joints to dissipate 5W. Again it will
get noticeably warm, even "hot", but not beyond anything the wire, solder,
and a ordinary circuit board should be able to handle.
********************************************************************
Embed Inc, Littleton Massachusetts, http://www.embedinc.com/products
(978) 742-9014. Gold level PIC consultants since 2000.