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regexp_replace grief

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Armin Resch

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Apr 10, 2013, 7:59:29 PM4/10/13
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Not sure this is the right list to vent about this but here you go:

I) select regexp_replace('BEFORE.AFTER','(.*)\..*','\1','g') "Substring"
II) select regexp_replace('BEFORE.AFTER','(.*)\\..*','\\1','g') "Substring"

Executing (II) against pg 8.4.4 or 9.0.4 yields 'BEFORE', but in order for 9.1.7 to yield the same one has to execute (I) .. bummer

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Craig James

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Apr 10, 2013, 9:08:51 PM4/10/13
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This has nothing to do with regexp's.  It's a change in how '\' is interpreted in any quoted string.  The change came with Postgres 9.x and is documented in the release notes.  It brings Postgres into compliance with the SQL standard.

In Perl, I do something like this:

my $pg_bs_char;
if ($dbh->get_info($GetInfoType{SQL_DBMS_VER}) gt "09.00.00") {
    $pg_bs_char = "\\";         # a single '\' for PG 9.1 and higher
} else {
    $pg_bs_char = "\\\\";       # a double '\\' for PG up to 9.0
}

You can also revert to the old 8.x interpretation; see

  http://www.postgresql.org/docs/9.1/static/runtime-config-compatible.html

Craig
 

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Armin Resch

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Apr 10, 2013, 9:22:13 PM4/10/13
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Thx for clarification, Craig. Your Perl snippet comes in handy, too.
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