Bisesh,
These reactions are possible. Would you be willing to share your mass action equations (A + B -> C + D) and the desired rate expressions. If proprietary, you are welcome to send them directly to me.
Glenn
From:
pflotra...@googlegroups.com <pflotra...@googlegroups.com> on behalf of Bisesh Joshi <bjo...@udel.edu>
Date: Thursday, June 12, 2025 at 9:47 AM
To: pflotra...@googlegroups.com <pflotra...@googlegroups.com>
Subject: [pflotran-users: 8430] Queries on simulating SOM decomposition in aerobic and anaerobic conditions
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SOM + 24Fe3+ + 13H2O→NH4+ + 6HCO3− + 24Fe2+ + 29H+ (anaerobic conditions, O2 inhibiting this reaction)
Additionally, Fe3+ here also comes from the mineral Goethite.
On a different note, I have got this mineral reaction in one database: 'SOM1' 100. 3 12.0 'DOM1' -12.0 O2(aq) 1.0 NH4+ 100. 100. 100. 100. 100. 100. 100. 100. 180.1566 'TAO-glucose’. Doesn't this reaction imply that SOM1 is stable and not producing DOM1 here?
Thanks again for your help.
Best regards
Bisesh
From:
pflotra...@googlegroups.com <pflotra...@googlegroups.com> on behalf of Bisesh Joshi <bjo...@udel.edu>
Date: Friday, June 13, 2025 at 10:27 AM
To: pflotra...@googlegroups.com <pflotra...@googlegroups.com>
Subject: Re: [pflotran-users: 8434] Queries on simulating SOM decomposition in aerobic and anaerobic conditions
Hi Glenn,
Thanks for the response.
This is what I'm thinking: I want to use SOM (C6H13NO5) as a mineral, producing the following products in aerobic and anaerobic conditions.
SOM + 6O2 + H2O→NH4+ + 6HCO3− + 5H+ (aerobic conditions)
SOM + 24Fe3+ + 13H2O→NH4+ + 6HCO3− + 24Fe2+ + 29H+ (anaerobic conditions, O2 inhibiting this reaction)
Additionally, Fe3+ here also comes from the mineral Goethite.
These reactions can be modeled once SOM -> DOM using the MICROBIAL_REACTIONs with multiplicative Monod and inhibition factors. Otherwise, you will need a reaction sandbox to implement the rate expressions using SOM as the donor.
On a different note, I have got this mineral reaction in one database: 'SOM1' 100. 3 12.0 'DOM1' -12.0 O2(aq) 1.0 NH4+ 100. 100. 100. 100. 100. 100. 100. 100. 180.1566 'TAO-glucose’. Doesn't this reaction imply that SOM1 is stable and not producing DOM1 here?
Thanks again for your help.
The mass action equation for this reaction is
SOM + 12 O2(aq) -> 12 DOM + NH4+
This mineral reaction produces 12 moles of DOM for each mole of SOM consumed. If you use this mineral reaction, you need to specify DISSOLUTION_RATE_CONSTANT and PRECIPITATION_RATE_CONSTANT and set the precipitation constant to zero to avoid re-precipitating the SOM.
Glenn
Best regards
Bisesh
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