Is this the correct behaviour

[Kiran Kumar]

Hi ,
Is this behaviour correct when i print $_ ? ..

#!/usr/bin/pugs
use v6;

for (0 .. 8) -> $tmp
{
say "tmp is $tmp \n";
}

for (0 .. 8) -> $tmp
{
say " tmp is $tmp Spcl is $_ \n";
}

Output is

tmp is 0

tmp is 1

tmp is 2

tmp is 3

tmp is 4

tmp is 5

tmp is 6

tmp is 7

tmp is 8

tmp is 0 Spcl is 1

tmp is 2 Spcl is 3

tmp is 4 Spcl is 5

tmp is 6 Spcl is 7

tmp is 8 Spcl is

~Kiran

[Luke Palmer]

Kiran Kumar writes:
> Hi ,
> Is this behaviour correct when i print $_ ? ..
>
>
> #!/usr/bin/pugs
> use v6;
>
> for (0 .. 8) -> $tmp
> {

> say " tmp is $tmp Spcl is $_ \n";

> }
>
> tmp is 0 Spcl is 1
>
> tmp is 2 Spcl is 3
>
> tmp is 4 Spcl is 5
>
> tmp is 6 Spcl is 7
>
> tmp is 8 Spcl is

Nope. It seems that pugs is considering $tmp and the implicit usage of
$_ to specify two different parameters to the block. In fact, there's
only one: $tmp, and it is aliased to $_.

Luke

[Aaron Sherman]

On Mon, 2005-04-25 at 08:43, Luke Palmer wrote:

> Nope. It seems that pugs is considering $tmp and the implicit usage of
> $_ to specify two different parameters to the block. In fact, there's
> only one: $tmp, and it is aliased to $_.

Ah, and this was my problem too. Thanks, Luke or whoever fixed this one.

--
Aaron Sherman <a...@ajs.com>
Senior Systems Engineer and Toolsmith
"It's the sound of a satellite saying, 'get me down!'" -Shriekback

[Kiran Kumar]

I Dont think this is fixed , Im still getting this Error .

for (0 .. 8) -> $tmp
{
say " tmp is $tmp Spcl is $_ \n";
}

[Aaron Sherman]

On Tue, 2005-04-26 at 13:46 +0530, Kiran Kumar wrote:
> I Dont think this is fixed , Im still getting this Error .
>
> for (0 .. 8) -> $tmp
> {
> say " tmp is $tmp Spcl is $_ \n";
> }

Interesting. Now, it's dependent on the use of $_. Take out that $_ and
it works fine... cool bug ;-)