[perl #67050] $str.Num should be the same as +$str

[Moritz Lenz]

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13:52 < zulon> rakudo: say "3".Num
13:52 < p6eval> rakudo d95def: OUTPUT«Method 'Num' not found for
invocant of class 'Str'␤»
13:52 <@moritz_> zulon: that should work

[Brandon S. Allbery KF8NH]

I thought unary + was scalar/item? context in perl6, not numify.

--
brandon s. allbery [solaris,freebsd,perl,pugs,haskell] all...@kf8nh.com
system administrator [openafs,heimdal,too many hats] all...@ece.cmu.edu
electrical and computer engineering, carnegie mellon university KF8NH

[Mark J. Reed]

On Tue, Jun 30, 2009 at 4:55 AM, Brandon S. Allbery
KF8NH<all...@ece.cmu.edu> wrote:
> I thought unary + was scalar/item? context in perl6, not numify.

 + is numeric context - which is one of several subtypes of item
context. Generic item context is item(); + numifies; ? boolifies; ~
stringifies.

I'm guessing you saw + used to get the length of an array, and that's
where you got that it's equivalent to P5 scalar().

--
Mark J. Reed <mark...@gmail.com>

[perl6-bug...@perl.org]

On Tue Jun 30 01:56:39 2009, all...@ece.cmu.edu wrote:
> I thought unary + was scalar/item? context in perl6, not numify.

When in doubt, check the spec. :)

S03 (]):
] Unlike in Perl 5, where + is a no-op, this operator coerces to
] numeric context in Perl 6.

So prefix:<~> stringifies, prefix:<+> numifies, and prefix<?> boolifies.
There's some kind of nice symmetry to that, isn't there?