OEE

[jafar]

three method & for OEE
The example covered 240 blocks of 10 minutes. Assume an accredited
rate of 4 units per minute (15 seconds cycle time) and 3.5 percent
waste or 96.5 percent yield for normal production activity.

Actual units produced =(1000 minutes x 4 per minute) + (340 x 2 per
minute) = 4680, including
160 contaminated (no good) units.
Number of good units produced = (4680 — 160) x 0.965 = 4362 good units
Overall quality rate = number of good units/total units = 0.932

Method 1—Using Nakajima formulas

Loading time = 2400 — 570 = 1830 minutes
Availability = (1830 — 490) / 1830 = 0.732
Units produced = 4680
Actual cycle time = [(1000 + 340) / 4680] x 60 = 17.18 seconds
Operating speed rate = 15 seconds / 17.18 seconds = 0.873
Performance efficiency = 1.0 x [4680 x (15/60)] / 1340 = 0.883

OEE = 0.732 x 0.873 x 0.932 = 59.6%

Method 2—Using event time records

Scheduled time = 2400 — 570 = 1830 minutes
Run time = 1000 + 340 = 1340 minutes
Speed rate = [(1000 x 1.0) + (340 x ½)] / 1340 = 0.873
Availability = 1340 / 1830 = 0.732

OEE = 0.732 x 0.873 x 0.932 = 59.6%

Method 3—Using product based calculations

Theoretical run time = 4362 good units produced / 4 per min = 1090.5
min
Schedule time = 2400 — 570 = 1830 minutes

OEE = 1090.5 / 1830 = 59.6%

j-akbari from partsazan forging