Repetition of the same app

[Fabian Gerstmeier]

Hello, 

sorry if this question has been answered before but I am new to oTree and cannot figure out a good answer on my own. 

I have an original game that is 4 rounds long. Now I want to repeat this game several times and randomly assign the participants into new groups. 

Is there a smart way to do that?

Of course I can copy and paste the original app and make a sequence of these copy-paste apps. But I am reluctant to do so since I would have a lot of code repetition. 

(If this is the suggested answer. Is there an easy way randomly select one of the apps to be payment relevant)

I really appreciate any help 

Best

Fabi

[Chris @ oTree]

How about making a 16 round game?

Sent from my phone

On Mar 31, 2021, at 12:00 AM, Fabian Gerstmeier <fabgers...@gmail.com> wrote:

Hello, 

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[Fabian Gerstmeier]

Sadly not really working I guess. I was not precise enough in the initial question. 

One Period can go from 1-4 rounds depending on the decisions. Hence, if say I want 5 Periods (5 repetition of the initial game) there could be 5 rounds or 20 rounds depending on the decisions of the participants. 

Also I guess it will be weird working with in_all_rounds() etc. since it will count over all rounds and not only over one Period(1-4 rounds) which I want. 

But thank you for the fast reply and  I will think about it more!

Best,

Fabian

[Chris @ oTree]

It can still be done. You just need to track the current period & round number yourself, and use those instead of the built-in .round_number. Make field on the group like:

current_period = models.IntegerField()

round_in_period = models.IntegerField()

Then in each round, you decide if the period is finished. If yes, then increment the field by 1. (You can also store current_period as a participant field.)

Instead of .in_all_rounds(), you could use a function like this:

def in_all_period_rounds(group):

    current_round = group.round_number

    first_round_in_period = group.round_number - group.round_in_period + 1)

    return group.in_rounds(first_round_in_period, current_round)

[Fabian Gerstmeier]

Thank you I will try that! 

Best

Fabian

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