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如何实现request path的通配符匹配呢?
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lua
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Kelvin Kuo
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Apr 10, 2019, 6:07:09 AM
4/10/19
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我的需求是,openresty做一个ip拦截网关,同时我支持path白名单,可以让使用者灵活的配置可以忽略的path。比如
www.weibo.com/userinfo/*
, *.
weibo.com/userinfo/
。因为lua原生不支持正则表达式,我不能要求所有业务方都学习lua的string.find() 语法,所以,是否有简单的方法支持wildcard匹配呢?
ytl m
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Apr 10, 2019, 6:09:44 AM
4/10/19
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看下ngx.re.match或者ngx.re.find相关接口是不是满足你的需求呢
在 2019年4月10日星期三 UTC+8下午6:07:09,Kelvin Kuo写道:
Kelvin Kuo
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Apr 11, 2019, 4:58:58 AM
4/11/19
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谢谢,通配符对业务人员更友好,但是正则也可以接受把,就用ngx.re.match了。
along
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Apr 11, 2019, 5:03:58 AM
4/11/19
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不客气的,用ngx.re.match的时候要注意性能哦
在 2019年4月11日星期四 UTC+8下午4:58:58,Kelvin Kuo写道:
Kelvin Kuo
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Apr 11, 2019, 5:05:38 AM
4/11/19
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“jo”是吧?
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