Debugging Gulp fails in Chrome

[rej...@gmail.com]

Hi,

I have followed the article (https://stackoverflow.com/questions/40033298/how-to-debug-a-gulp-task) to debug gulp file using chrome. My gulpfile.js looks like this:

var gulp = require('gulp');

// Gulp 4

debugger;

gulp.task('cleanTemp', function (done) {

console.log('Hello world!');

done();

});

When I execute the command from my working folder:

node --inspect-brk ./node_modules/gulp/node_modules/.bin/gulp cleanTemp

I am getting an error:

Debugger attached.

C:\Workspace\Projects\Eclipse\CommsProc\Source\HttpServer\node_modules\gulp\node_modules\.bin\gulp:2

basedir=$(dirname "$(echo "$0" | sed -e 's,\\,/,g')")

          ^^^^^^^

SyntaxError: missing ) after argument list

    at createScript (vm.js:80:10)

    at Object.runInThisContext (vm.js:139:10)

    at Module._compile (module.js:617:28)

    at Object.Module._extensions..js (module.js:664:10)

    at Module.load (module.js:566:32)

    at tryModuleLoad (module.js:506:12)

    at Function.Module._load (module.js:498:3)

    at Function.Module.runMain (module.js:694:10)

    at startup (bootstrap_node.js:204:16)

    at bootstrap_node.js:625:3

Waiting for the debugger to disconnect...

What am I doing wrong. What does this message mean: basedir=$(dirname "$(echo "$0" | sed -e 's,\\,/,g')")

Kind Regards,

Janusz

[Rashik Ansar Shaik]

i think its __dirname 

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[rej...@gmail.com]

Yeah. But what about dirname. Any solution?

Kind Regards,

Janusz